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tester [92]
3 years ago
9

Select the best answer for the question. 6. The first step in using time more efficiently is A. studying how successful people u

se time. B. getting to bed earlier. C. developing a plan. D. limiting recreational activities.
Physics
2 answers:
SIZIF [17.4K]3 years ago
6 0
I would say C.
Developing a plan is important because it will motivate you and tell you when to get things done. It is the most efficient

Hope this helped :)
xxTIMURxx [149]3 years ago
3 0
Hey there!

The first step in using time more effectiantly is to develop a plan. First, you would want to plan how you are going to save your time before you just get a bunch of ideas.

Hope this helps
Have a great day (:
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An American Red Cross plane needs to drop emergency supplies to victims of a hurricane in a remote part of the world. The plane
Andreas93 [3]
Refer to the diagram shown below.

Assume that air resistance is ignored.

Note:
The distance, h, of a falling object with initial vertical velocity of zero at time t is
h = (1/2)gt²
where
g = 9.8 m/s²

The initial vertical velocity of the supplies is 0 m/s.
It the time taken for the supplies to reach the ground is t, then
(50 m) = (1/2)*(9.8 m/s²)*(t s)²

Hence obtain
t² = 50/4.9 = 10.2041
t = 3.1944 s

The horizontal distance traveled at a speed of 100 m/s is
d = (100 m/s)*(3.1944 s) = 319.44 m

Answer: 319.4 m (nearest tenth)

3 0
4 years ago
Two air track carts move along an air track towards each other. Cart A has a mass of 450 g and moves toward the right with a spe
Blizzard [7]

Answer:

The right answer is D) the total momentum of the system is 0.047 kg · m/s toward the right.

Explanation:

Hi there!

The total momentum of the system is given by the sum of the momentum vectors of each cart. The momentum is calculated as follows:

p = m · v

Where:

p = momentum.

m = mass.

v = velocity.

Then, the momentum of the system will be the momentum of cart A plus the momentum of cart B (let´s consider the right as the positive direction):

mA · vA + mB · Vb

0.450 kg · 0.850 m/s + 0.300 kg · (- 1.12 m/s) = 0.047 kg · m/s

The right answer is D) the total momentum of the system is 0.047 kg · m/s toward the right.

6 0
3 years ago
The potential energy of a 35 kg cannon ball is 14000 J. How high was the cannon ball to have this much potential energy?
Anettt [7]

From the information given, cannon ball weighs 40 kg and has a potential energy of 14000 J.

We need to find its height.

We will use the formula P.E = mgh

Therefore h = P.E / mg

where P.E is the potential energy,

m is mass in kg,  

g is acceleration due to gravity (9.8 m/s²)

h is the height of the object's displacement in meters.

h = P.E. / mg

h = 14000 / 40 × 9.8

h = 14000 / 392

h = 35.7

Therefore the canon ball was 35.7 meters  high.

6 0
3 years ago
Earthquakes usually happen at: - folds - mountains - fault lines
anastassius [24]

Answer:

Fault lines

Explanation:

8 0
3 years ago
A particle of mass M moves along a straight line with initial speed vi. A force of magnitude F pushes the particle a distance D
LenaWriter [7]

Answer:

vf = √(vi²+2*(F/m)*D)

Explanation:

Given

Mass of the particle: M

Initial speed of the particle: vi

Force: F

Distance: D

We can apply the formula

F = M*a   ⇒    a = F/m

then we use the equation

vf = √(vi²+2*a*D)

⇒  vf = √(vi²+2*(F/m)*D)

6 0
3 years ago
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