Refer to the diagram shown below.
Assume that air resistance is ignored.
Note:
The distance, h, of a falling object with initial vertical velocity of zero at time t is
h = (1/2)gt²
where
g = 9.8 m/s²
The initial vertical velocity of the supplies is 0 m/s.
It the time taken for the supplies to reach the ground is t, then
(50 m) = (1/2)*(9.8 m/s²)*(t s)²
Hence obtain
t² = 50/4.9 = 10.2041
t = 3.1944 s
The horizontal distance traveled at a speed of 100 m/s is
d = (100 m/s)*(3.1944 s) = 319.44 m
Answer: 319.4 m (nearest tenth)
Answer:
The right answer is D) the total momentum of the system is 0.047 kg · m/s toward the right.
Explanation:
Hi there!
The total momentum of the system is given by the sum of the momentum vectors of each cart. The momentum is calculated as follows:
p = m · v
Where:
p = momentum.
m = mass.
v = velocity.
Then, the momentum of the system will be the momentum of cart A plus the momentum of cart B (let´s consider the right as the positive direction):
mA · vA + mB · Vb
0.450 kg · 0.850 m/s + 0.300 kg · (- 1.12 m/s) = 0.047 kg · m/s
The right answer is D) the total momentum of the system is 0.047 kg · m/s toward the right.
From the information given, cannon ball weighs 40 kg and has a potential energy of 14000 J.
We need to find its height.
We will use the formula P.E = mgh
Therefore h = P.E / mg
where P.E is the potential energy,
m is mass in kg,
g is acceleration due to gravity (9.8 m/s²)
h is the height of the object's displacement in meters.
h = P.E. / mg
h = 14000 / 40 × 9.8
h = 14000 / 392
h = 35.7
Therefore the canon ball was 35.7 meters high.
Answer:
vf = √(vi²+2*(F/m)*D)
Explanation:
Given
Mass of the particle: M
Initial speed of the particle: vi
Force: F
Distance: D
We can apply the formula
F = M*a ⇒ a = F/m
then we use the equation
vf = √(vi²+2*a*D)
⇒ vf = √(vi²+2*(F/m)*D)