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katrin [286]
2 years ago
5

Minor partial melting in the asthenosphere causes liquid magma to form. If the molten rock is able to move at all, it will leave

behind the heavier solid rock that did not melt. In what direction is the molten rock most likely to move through the asthenosphere? Explain why using the concepts of density and pressure.
Chemistry
1 answer:
Bad White [126]2 years ago
6 0
I don’t understand the question be more specific or take a picture
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A scientist is researching the solar system. How can the scientist best add to existing empirical evidence about the solar syste
Bogdan [553]

Answer:

The correct option is;

c. The scientist can make and record observations

Explanation:

Empirical evidence are evidences obtained by direct observation, sensual perception or direct measurement. It is the processed and useful data gathered and stored in a material form or documented to provide record of the measurement.

With the aid of empirical evidence, it is possible for researchers to find answers to question regarding topics that can vastly impact every day life.

With empirical evidence, it is possible to determine the effects of treatment in a study such as the invention of working car safety devices such as seat belts and airbags.

7 0
3 years ago
A bomb calorimeter has a heat capacity of 675 J/°C and contains 925 g of water. If the combustion of 0.500 mole of a hydrocarbon
ikadub [295]

<u>Answer:</u> The enthalpy of the reaction is 269.4 kJ/mol

<u>Explanation:</u>

To calculate the heat absorbed by the calorimeter, we use the equation:

q_1=c\Delta T

where,

q = heat absorbed

c = heat capacity of calorimeter = 675 J/°C

\Delta T = change in temperature = T_2-T_1=(53.88-24.26)^oC=29.62^oC

Putting values in above equation, we get:

q_1=675J/^oC\times 29.62^oC=19993.5J

To calculate the heat absorbed by water, we use the equation:

q_2=mc\Delta T

where,

q = heat absorbed

m = mass of water = 925 g

c = heat capacity of water = 4.186 J/g°C

\Delta T = change in temperature = T_2-T_1=(53.88-24.26)^oC=29.62^oC

Putting values in above equation, we get:

q_2=925g\times 4.186J/g^oC\times 29.62^oC=114690.12J

Total heat absorbed = q_1+q_2

Total heat absorbed = [19993.5+114690.12]J=134683.62J=134.7kJ

To calculate the enthalpy change of the reaction, we use the equation:

\Delta H_{rxn}=\frac{q}{n}

where,

q = amount of heat absorbed = 134.7 kJ

n = number of moles of hydrocarbon = 0.500 moles

\Delta H_{rxn} = enthalpy change of the reaction

Putting values in above equation, we get:

\Delta H_{rxn}=\frac{134.7kJ}{0.500mol}=269.4kJ/mol

Hence, the enthalpy of the reaction is 269.4 kJ/mol

6 0
3 years ago
Read 2 more answers
The below given compound is slightly soluble in water.
nordsb [41]

Answer:

an alkali

Explanation:

an alkali is a base that is slightly soluble in water

4 0
2 years ago
The boiling point of a substance is affected by
aev [14]
How strong the bonds are between the atoms
7 0
3 years ago
2. List and explain the three steps for solving a numeric problem.
Charra [1.4K]

Answer:

The steps for solving a numeric word problem are analyze, calculate, and evaluate. To solve a word problem, you must first determine where you are starting from (identify what is known) and where you are going (identify the unknown).

6 0
3 years ago
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