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3 years ago

How does the cardiovascular system help the body get rid of waste??

2 answers:

8 0

Not the rectum but the kidneys. cardiovascular system involves the blood flow and the urination to get rid of wastes. as the body had damaged blood cells or worn down cells, it moves the cells through three processes. respiration, when the cells are obtaining oxygen, then perspiration, when the blood or oxygen is used during motion or sleep, the body will emit heat and eventually move to the final stage whish it felicitation, when the body gets rid of unwanted wastes like bacteria, salts and excess liquids, through urination, the rectum moves SOLID wastes like the skin of the foods you eat, carbohydrates, and proteins that your body cannot use anymore. so your answer is partially correct but it is through facilitation.

Pani-rosa [81]3 years ago

4 0

The answer is the rectum

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How many oxygen atoms are in one molecule of baking soda

8_murik_8 [283]

NaHCO3 = No. of atoms are 1 sodium + 1 Hydrogen + 1 carbon + 3 oxygens = 6 atoms per molecule.

so a total of 3 oxygens

4 0

3 years ago

If 25.3 grams of mercury(II) oxide react to form 23.4 grams of mercury, how many grams of oxygen must simultaneously be formed?

sergij07 [2.7K]

Answer : The mass of oxygen formed must be 3.8 grams.

Explanation :

Law of conservation of mass : It states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

The balanced chemical reaction will be,

$2HgO\rightarrow 2Hg+O_2$

According to the law of conservation of mass,

Total mass of reactant side = Total mass of product side

Total mass of $2HgO$ = Total mass of $2Hg+O_2$

As we are given :

The mass of $HgO$ = 25.3 grams

The mass of $Hg$ = 23.4 grams

So,

$2\times 25.3g=2\times 23.4g+\text{Mass of }O_2$

$50.6g=46.8g+\text{Mass of }O_2$

$\text{Mass of }O_2=3.8g$

Therefore, the mass of oxygen formed must be 3.8 grams.

6 0

3 years ago

Find the final equilibrium temperature when 15.0 g of milk at 13.0 degrees c is added to 148 g of coffee with a temperature of 8

user100 [1]

According to zeroth law of thermodynamics, when two objects are kept in contact, heat (energy) is transferred from one to the other until they reach the same temperature (are in thermal equilibrium). When the objects are at the same temperature there is no heat transfer.

So, at equilibrium, $q_{lost}$ = $q_{gain}$ , $q_{lost}= q_{milk}$ + $q_{coffee}$

q=m×c×T, where q = heat energy, m = mass of a substance, c = specific heat (units J/kg∙K), T is temperature

$q_{lost}= (15X13X4.19)+(148X88.3X4.19), (15+148)X4.19XT_{final}$ =(15X13X4.19)+(148X88.3X4.19)

$T_{final}$ = 81.37 ° C

6 0

3 years ago

What are the units used to measure specific heat capacity?

Andrews [41]

The units used to measure specific heat capacity is Joules per kilogram per Kelvin.

<h3>What is specific heat capacity?</h3>

It is the amount of heat absorbed per kilogram of material when the temperature rises by 1 Kelvin.

Specific heat capacity C is the Joules of energy in form of heat per kilogram per Kelvin temperature. The units represented by

C = ___ J/kg.K

Thus, the units used to measure specific heat capacity is Joules per kilogram per Kelvin.

Learn more about specific heat capacity.

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2 years ago

Help this is my test

miss Akunina [59]

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3 years ago

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