2 moles x 6.02 x 10^23 maybe
Disodium inosinate is the disodium salt of inosinic acid with the chemical formula C10H11N4Na2O8P. It is used as a food additive and often found in instant noodles, potato chips, and a variety of other snacks. Although it can be obtained from bacterial fermentation of sugars, it is often commercially prepared from animal sources.
Answer:
Your cation is Pb2+
Explanation:
This is the explanation by chemical reactions
HCl (l) ----> H+(aq) + Cl-(aq)
Pb2+(aq) + 2Cl-(aq) ---> PbCl2 (s) ↓
H2SO4 (l) ----> 2H+ (aq) + SO4-2(aq)
Pb2+(aq) + SO4-2(aq) ---> PbSO4 (s) ↓
NaOH (l) ---> Na+(aq) + OH-(aq)
Pb2+(aq) + 2OH-(aq) ---> Pb(OH)2 (s) ↓
If the reaction takes place in a strong alkaline medium, lead hydroxide dissolves in excess of base
Answer:
![[H_2]_{eq}=0.183M](https://tex.z-dn.net/?f=%5BH_2%5D_%7Beq%7D%3D0.183M)
![[I_2]_{eq}=0.183M](https://tex.z-dn.net/?f=%5BI_2%5D_%7Beq%7D%3D0.183M)
![[HI]_{eq}=0.025M](https://tex.z-dn.net/?f=%5BHI%5D_%7Beq%7D%3D0.025M)
Explanation:
Hello.
In this case, for this equilibrium problem, we first realize that at the beginning there is just HI, it means that the reaction should be rewritten as follows:
Whereas the law of mass action (equilibrium expression) is:
![Kc=\frac{[H_2][I_2]}{[HI]^2}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BH_2%5D%5BI_2%5D%7D%7B%5BHI%5D%5E2%7D)
That in terms of initial concentrations and reaction extent or change 
turns out:
![Kc=\frac{x*x}{([HI]_0-2x)^2}\\\\54.3=\frac{x^2}{(0.391M-2x)^2}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7Bx%2Ax%7D%7B%28%5BHI%5D_0-2x%29%5E2%7D%5C%5C%5C%5C54.3%3D%5Cfrac%7Bx%5E2%7D%7B%280.391M-2x%29%5E2%7D)
And the solution via solver or quadratic equation is:
Whereas the correct answer is 0.183 M since the other value yield a negative concentration of HI at equilibrium (0.391-2*0.210=-0.029M).This, the equilibrium concentrations are:
![[HI]_{eq}=0.391M-2*0.183M=0.025M](https://tex.z-dn.net/?f=%5BHI%5D_%7Beq%7D%3D0.391M-2%2A0.183M%3D0.025M)
Regards.
Answer:
Explanation:
<u>1. Number of moles of gasoline</u>
a) Convert 60.0 liters to grams
- mass = 0.77kg/liter × 60.0 liter = 46.2 kg
- 46.2kg × 1,000g/kg = 46,200g
b) Convert 46,200 grams to moles
- molar mass of C₈H₁₈ = 114.2 g/mol
- number of moles = mass in grams / molar mass
- number of moles = 46,200g / (114.2 gmol) = 404.55 mol
<u>2. Number of moles of carbon dioxide, CO₂ produced</u>
a) Balanced chemical equation (given):
- C₈H₁₈ (l) + ²⁵/₂ O₂ (g) → 8 CO₂ (g) + 9 H₂O (g)
b) mole ratio:
- 1 mol C₈H₁₈ / 8 mol CO₂ = 404.55 mol C₈H₁₈ / x
Solve for x:
- x = 404.55mol C₈H₁₈ × 8 mol CO₂ / 1mol C₈H₁₈ = 3,236.4 mol CO₂
<u> 3. Convert the number of moles of carbon dioxide to volume</u>
Use the ideal gas equation:
- R = 0.08206 (mol . liter)/ (K . mol)
Substitute and compute:
- V =3,236.4 mol × 0.08206 (mol . liter) / (K . mol) 298.15K / 1 atm
Round to two significant figures (because the density has two significant figures): 79,000 liters ← answer
