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kykrilka [37]
3 years ago
15

CNC NaCl HCL are all classified as

Chemistry
1 answer:
Leona [35]3 years ago
6 0
<span>A) elements and compounds. Compounds are two combined elements.</span>
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The following two compounds are constitutional isomers. Identify which of these is expected to be more acidic, and explain your
Vladimir [108]

Answer:

c. Compound 2 is more acidic because its conjugate base is more resonance stabilized

Explanation:

You haven't told us what the compounds are, so let's assume that the formula of Compound 1 is HCOCH₂OH and that of Compound 2 is CH₃COOH.

The conjugate base of 2 is CH₃COO⁻. It has two important resonance contributors, and the negative charge is evenly distributed between the two oxygen atoms.

CH₃COOH + H₂O ⇌ CH₃COO⁻ + H₃O⁺

The stabilization of the conjugate base pulls the position of equilibrium to the right, so the compound is more acidic than 1.

6 0
3 years ago
What is the most striking part of this simulation?
oee [108]
None of the alpha particles fired at the foil are being repelled back, like they were in the Rutherford atom simulation.I hope this correct.

3 0
3 years ago
A naturally occurring oil co-distills with water to produce an oil/water distillate that is 20% oil by weight. If the molecular
Gelneren [198K]

Answer:

Explanation:

Partial pressure of oil = mole fraction of oil x total pressure

mole fraction of oil = mole of oil / mole of water + mole of oil

= mole of oil = mass of oil / molecular weight of oil

= 20 / 100 = .2

mole of water = 80 / 18

= 4.444

mole fraction of oil =  .2 / .2 + 4.444

= .2 / 4.644

Partial pressure of oil = mole fraction of oil x total pressure

= (.2 / 4.644 ) x 760 mm

= 32.73 mm Hg .

3 0
3 years ago
How many valence electrons does an atom of rubidium (Rb atomic number 37) have? A.One B.Five C.Six D.37
nadezda [96]
Electronic configuration of Rb: 2.8.8.8.8.3
Valence electron is 3....
4 0
3 years ago
Read 2 more answers
A 76.0-gram piece of metal at 96.0 °C is placed in 120.0 g of water in a calorimeter at 24.5 °C. The final temperature in the ca
Phoenix [80]

The specific heat capacity of the metal given the data from the question is 0.66 J/gºC

<h3>Data obtained from the question</h3>
  • Mass of metal (M) = 76 g
  • Temperature of metal (T) = 96 °C
  • Mass of water (Mᵥᵥ) = 120 g
  • Temperature of water (Tᵥᵥ) = 24.5 °C
  • Equilibrium temperature (Tₑ) = 31 °C
  • Specific heat capacity of the water (Cᵥᵥ) = 4.184 J/gºC
  • Specific heat capacity of metal (C) =?

<h3>How to determine the specific heat capacity of the metal</h3>

The specific heat capacity of the sample of the metal can be obtained as follow:

Heat loss = Heat gain

MC(M –Tₑ) = MᵥᵥCᵥᵥ(Tₑ – Tᵥᵥ)

76 × C × (96 – 31) = 120 × 4.184 × (31 – 24.5)

C × 4940 = 3263.52

Divide both side by 4940

C = 3263.52 / 4940

C = 0.66 J/gºC

Learn more about heat transfer:

brainly.com/question/6363778

#SPJ1

6 0
1 year ago
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