Answer:
Break up the soil to increase the number of pores should be your answer.
Explanation:
If you do that it will increase the amount of water in the plant.
Answer:
It represents the <em>number of atoms</em> of that particular element present in the compound. In C₂H₄O₂ there are 2 Carbon atoms, 4 Hydrogen atoms and 2 Oxygen atoms.
The balanced reaction
that describes the reaction between carbon monoxide and oxygen to produce
carbon dioxide is expressed co(g)+ ½o2(g) <span>→ </span>co2(g). The heat of combustion is 67.6 kcal per mole CO. We are given with 14 grams CO. Convert this to mole equal to 0.5 mole. Hence the total heat is 33.8 kcal.
Answer is: Move from the negatively charged body to the positively charged body.
The electron (symbol: e⁻) is a subatomic particle whose electric charge is negative one elementary charge.
The proton (p⁺) is subatomic particle with a positive electric charge of +1e elementary charge.
Opposite charges (positive and negative) attract one another.
The negatively charged body has extra electrons, more electrons than protons.
The positively charged body has less electrons than protons.
Answer:
you must add 50 mL
Explanation:
Hi
KOH is a strong base and by adding 100mL 0.05M you will have an amount of 5 millimol.
NaCN is a base and by adding 50 mL 0,150 M you will have an amount of 7,5 mmol.
HCl is a acid and by adding 200 mL 0,075 M you will have an amount of 15 mmol.
The acid reacts with the bases leaving 2.5 mmol unreacted.
Na3PO4 is a base and by adding 50 mL 0,1 M you will have an amount of 5 mmol.
The 2.5 mmol of acid react with the base PO4 ^ -3 forming a regulatory solution of PO4 ^ -3 and HPO4 ^ -2 of pKa 2.12
5 mmol of acid (HNO3) must be added to obtain a regulatory solution formed by the same amount of HPO4 ^ -2 (2.5 mmol) and H2PO4 ^ -1 (2.5 mmol) with pKa 7.21
Considering a quantity of 5 mmol of HNO3 of concentration 0.1 M, 50 mL must be added.
To calculate the pH of the regulatory solution you should consider pH = pKa × Ca / Cb pH = 7.21 × 2.5 / 2.5 = 7.21 Being in the same solution the volume is the same and can be simplified to achieve a faster calculation.
successes with your homework
