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3 years ago

Which Salt is least soluble at 50 C

Physics

1 answer:

Anvisha [2.4K]3 years ago

4 0

The salt $c e_{2}\left(s o_{4}\right)_{3}$ is the least soluble salt at 50 $^{\circ} \mathrm{C}$ .

Answer: Option 1

Explanation:

As it is clear that $c e_{2}\left(s o_{4}\right)_{3}$ , a gas so the solubility of it decreases on increasing the temperature of water. Because gas molecule starts to evaporate on attaining heat with the increase of temperature thus leading to reduction in the solubility of them.

As most of the gas molecules get vaporised the solubility in water gradually decreases for this compound. It is also clear from the solubility graphs of the various salts.

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Consider the speed of light in another universe to be only 100 m/s. Two cars are traveling along a highway in opposite direction

olganol [36]

Answer:

-62.45m/s and +62.45m/s

Explanation:

The formula for relativistic speed

This is the speed of A with respect to B

$V_{AB}=\frac{V_{A}-V_{B}}{1-\frac{V_{A}V_{B}}{C^2} }$

where

$V_{A}$ will be the velocity of person 1: 39m/s

$V_{B}$ will be the velocity of person 2: -31m/s (negative because is travelling in opposite direction)

and $C$ the velocity of light: 100m/s

The velocity of person 1 measured by person 2 is:

$V_{AB}=\frac{39m/s-(-31m/s)}{1-\frac{(39m/s)(-31m/s)}{(100m/s)^2}}=62.45m/s$

The velocity of person 2 measured by person 1 is:

$V_{BA}=\frac{V_{B}-V_{A}}{1-\frac{V_{B}V_{A}}{C^2} }$

$V_{BA}=\frac{-31m/s-39m/s}{1-\frac{(-31m/s)(39m/s)}{(100)^2} }=-62.45m/s$

8 0

2 years ago

The net force acting on an object equals the applied force plus the force of friction.

Georgia [21]

Answer:

False

Explanation:

The net force is equal to the applied force minus the force of friction. It is possible for friction to act in the same direction as an applied force, but that would mean there would have to be more than two forces acting on the object.

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2 years ago

) By observing that the centripetal acceleration of the Moon around the Earth is ac = 2.7 × 10-3 m/s2, what is the gravitatonal

Sedbober [7]

Answer:

G = 6,786 10⁻¹¹ m³ / s² kg

Explanation:

The law of universal gravitation is

F = G m M/ r²

Where G is the gravitational constant, m and M are the masses of the bodies and r is the distance from their centers

Let's use Newton's second law

F = m a

The acceleration is centripetal

a = $a_{c}$

We replace

G m M / r² = m $a_{c}$

G = $a_{c}$ r² / M

Let's replace and calculate

G = 2.7 10⁻³ (3.88 10⁸)² / 5.99 10²⁴

G = 6,786 10⁻¹¹ m³ / s² kg

Let's perform a dimensional analysis

[N m²/kg²] = [kg m/s² m² / kg²] = [m³ / s² kg]

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2 years ago

Which of the following forces can change velocity?

andrezito [222]

Unequal opposite forces.
(They're unbalanced.)

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Niels Bohr's important discovery was?

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2 years ago

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