A volumetric flow rate of 2 m^3/ s of liquid water is to be pumped from sea level to an elevation of 1200 m. Taking the density

Question

3 years ago

14

of the water is 1000 kg/m^3, calculate the minimum power requirement necessary to accomplish this task.

1 answer:

exis [7] · Answer 1 · 2022-02-22T08:00:36+03:00

Answer:

power requirement is 23.52 × $10^{6}$ W

Explanation:

given data

flow rate q = 2 m³/s

elevation h = 1200 m

density of the water ρ = 1000 kg/m³

to find out

power requirement

solution

we will get power by the power equation that is

power = ρ× Q× g× h ...................1

put here all value we get power

power = ρ× Q× g× h

power = 1000 × 2 × 9.8 × 1200

power = 23.52 × $10^{6}$

so power requirement is 23.52 × $10^{6}$ W