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3 years ago

14

a ball at rest starts rolling down a hill with a constant acceleration of 3.2 meters/second2. what is the final velocity of the

ball after 6.0 seconds

1 answer:

Y_Kistochka [10]3 years ago

6 0

Answer:

3.2(6.0) = 19.2 m/s

Explanation:

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For this case we have that by definition, the average power is given by:

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t: It's time

According to the data we have to:

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(b) If the force is constant, since the mass is constant and F = ma according to Newton's 2nd law, the acceleration on bullet is also constant

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At the time the bullet is coming to rest, $v(t) = 0, a = -57041.67 m/s^2$

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