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S_A_V [24]
4 years ago
14

Two events are observed in a frame of reference S to occur at the same space point, with the second event occurring after a time

of 1.70 s . In a second frame S' moving relative to S, the second event is observed to occur after a time of 2.25 s . What is the difference between the positions of the two events as measured in S'?

Physics
1 answer:
Deffense [45]4 years ago
5 0

Answer:

he difference between the positions of the two events as measured in S = 4.42 x 10 8 m

Explanation:

The concept of time dilation is applied to solve the question as shown in the attachment.

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Serhud [2]

Answer:

1362000 kgm/s

Explanation:

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After 15 seconds at an acceleration of 2 m/s2, the plane speed would be

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How much force is required to accelerate a 5 kg mass at 20 m/s^2
Studentka2010 [4]

Hello!

\large\boxed{F = 100N}

Use the equation F = m · a (Newton's Second Law) to solve. Substitute in the given values:

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3 years ago
when two object P and Q are supplied with the same quantity of heat, the temperature change in P is observed to be twice that of
Ahat [919]

<h2>When two object P and Q are supplied with the same quantity of heat, the temperature change in P is observed to be twice that of Q. The mass of P is half that of Q. The ratio of the specific heat capacity of P to Q​</h2>

Explanation:

Specific heat capacity

It is defined as amount of heat required to raise the temperature of a substance by one degree celsius .

It is given as :

Heat absorbed = mass of substance x specific heat capacity x rise in temperature

or ,

Q= m x c x t

In above question , it is given :

For Q

mass of Q = m

Temperature changed =T₂/2

Heat supplied = x

Q= mc t

or

X=m x C₁ X T₁

or, X =m x C₁ x T₂/2

or, C₁=X x 2 /m x T₂                                 (equation 1 )

For another quantity : P

mass of P =m/2

Temperature= T₂

Heat supplied is same that is : X

so, X= m/2 x C₂ x T₂                            

or, C₂=2X/m. T₂                                   (equation 2 )

Now taking ratio of C₂ to c₁, We have

C₂/C₁= 2X /m.T₂  /2X  /m.T₂

so, C₂/C₁= 1/1

so, the ratio is 1: 1

8 0
3 years ago
Describe how electricity flows through a simple closed circuit.
Vedmedyk [2.9K]

Answer:

Electrons are drawn from one end of the battery to the other. Connecting two of those ends allows an electric current to flow between them. Wires make a path through that current can flow from one end of a battery to the other end, which would be considered as: The north and east side

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Answer:

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1.4 Yes

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