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jeyben [28]
3 years ago
13

What is the formula for acceleration? ( PLEASE HELP! ALSO IF YOU GET B IT'S WRONG BECAUSE I ALREADY PUT THAT AND IT WAS WRONG so

rry caps)
A: Final speed-initial speed ________________________ time

B: Net force = Mass x acceleration

C: Mass x Velocity

D: Force a 5N Force B 10N Net force of forces A and B 15N
Physics
1 answer:
skad [1K]3 years ago
3 0

Answer:

option A is correct

Explanation:

acceleration the time rate of change of velocity or speed so

a=Δv/t

Δv=vf-vi  

Δv= final speed-initial speed

now a=final speed-initial speed/time

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Would a bottleneck event of the plants in an area from the video at the top of this page result in the need for primary or secon
andriy [413]

The bottleneck event of the plants in an area results in secondary succession.

<h2>What is bottleneck event?</h2>

A bottleneck is an event that drastically reduces the population size of an organism. The bottleneck may be caused by various events, such as an environmental disaster, the hunting or habitat destruction that results in the deaths of organisms.

<h3>Secondary succession</h3>

Secondary succession is a type of ecological succession in which plants and animals recolonize a habitat after a major disturbance such as a devastating flood, wildfire, landslide, lava flow, or human activity e.g., farming or road or building construction.

Learn more about succession here: brainly.com/question/1212975

7 0
2 years ago
The simple sugar made during photosynthesis is called _____.
Andre45 [30]

Answer:

glucose

Explanation:

3 0
3 years ago
Read 2 more answers
Consider the following distribution of objects: a 2.00-kg object with its center of gravity at (0, 0) m, a 2.20-kg object at (0,
adelina 88 [10]

Answer:

body position 4 is (-1,133, -1.83)

Explanation:

The concept of center of gravity is of great importance since in this all external forces are considered applied, it is defined by

               x_cm = 1 /M   ∑ x_{i} m_{i}

               y_cm = 1 /M   ∑ y_{i} mi

Where M is the total mass of the body, mi is the mass of each element

give us the mass and position of this masses

body 1

m1 = 2.00 ka

x1 = 0 me

y1 = 0 me

body 2

m2 = 2.20 kg

x2 = 0m

y2 = 5 m

body 3

m3 = 3.4 kg

x3 = 2.00 m

y3 = 0

body 4

m4 = 6 kg

    x4=?

   y4=?

mass center position

x_cm = 0

y_cm = 0

let's apply to the equations of the initial part

X axis

    M = 2.00 + 2.20 + 3.40

    M = 7.6 kg

    0 = 1 / 7.6 (2 0 + 2.2 0 + 3.4 2 + 6 x4)

     x4 = -6.8 / 6

     x4 = -1,133 m

Axis y

    0 = 1 / 7.6 (2 0 + 2.20 5 +3.4 0 + 6 y4)

    y4 = -11/6

    y4 = -1.83 m

body position 4 is (-1,133, -1.83)

7 0
3 years ago
Studies of sedimentary rocks and fossils have helped scientists understand the history of Earth. How is geologic time organized
grin007 [14]
Eras and then smaller periods based on geologic and biologic events that occurred during those times. According to geological time scale, there are six eras from the beginning some periods of few eras & then period is classified into smaller units called "epoch"

In short, Your Answer would be Option B

Hope this helps!
7 0
3 years ago
Read 2 more answers
Planets are not uniform inside. Normally, they are densest at the center and have decreasing density outward toward the surface.
SSSSS [86.1K]

Answer:

a = 9.94 m/s²

Explanation:

given,

density at center= 1.6 x 10⁴ kg/m³

density at the surface = 2100 Kg/m³

volume mass density as function of distance

\rho(r) = ar^2 - br^3

r is the radius of the spherical shell

dr is the thickness

volume of shell

dV = 4 \pi r^2 dr

mass of shell

dM = \rho(r)dV

\rho = \rho_0 - br

now,

dM = (\rho_0 - br)(4 \pi r^2)dr

integrating both side

M = \int_0^{R} (\rho_0 - br)(4 \pi r^2)dr

M = \dfrac{4\pi}{3}R^3\rho_0 - \pi R^4(\dfrac{\rho_0-\rho}{R})

M = \pi R^3(\dfrac{\rho_0}{3}+\rho)

we know,

a = \dfrac{GM}{R^2}

a = \dfrac{G( \pi R^3(\dfrac{\rho_0}{3}+\rho))}{R^2}

a =\pi RG(\dfrac{\rho_0}{3}+\rho)

a =\pi (6.674\times 10^{-11}\times 6.38 \times 10^6)(\dfrac{1.60\times 10^4}{3}+2.1\times 10^3)

a = 9.94 m/s²

7 0
3 years ago
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