Answer: Molar concentration of the tree sap have to be 0.783 M
Explanation:
To calculate the concentration of solute, we use the equation for osmotic pressure, which is:
where,
= osmotic pressure of the solution = 19.6 atm
i = Van't hoff factor = 1 (for non-electrolytes)
R = Gas constant = 
T = temperature of the solution = ![32^oC=[273+32]=305K](https://tex.z-dn.net/?f=32%5EoC%3D%5B273%2B32%5D%3D305K)
Putting values in above equation, we get:
Thus the molar concentration of the tree sap have to be 0.783 M to achieve this pressure on a day when the temperature is 32°C
this is a dilution question where a certain volume is taken from a more concentrated solution and diluted to make a solution with a lower concentration.
the dilution forumla is as follows
c1v1 = c2v2
where c1 is concentration and v1 is volume of the more concetrated solution
c2 is concentration and v2 is volume of the diluted solution
substituting the values in the equation
18.0 M x V = 0.126 M x 16.5 L
V = 0.1155 L
volume of 115.5 mL is taken from the 18.0 M solution and diluted upto 16.5 L solution.
Answer:
a party mix:-) it would be a jar of cashews, peanuts, almonds, ettc.
Explanation:
if you can separate the nuts, it is heterogenous
Answer:
studies
Explanation:
if they get plenty of studies then they get it
