Answer:
78.35°
Explanation:
THIS IS THE COMPLETE QUESTION BELOW;
A layer of ethyl alcohol (n = 1.361) is on top of water (n = 1.333). To the nearest degree, at what angle relative to the normal to the interface of the two liquids is light totally reflected?
From Snell's Law,
(ni)/(nr) = Sin (θr) / Sin (θi)
Where
θi = Angle of Incidence
θr = Angle of refraction
ni = Refractive index given for ethyl alcohol
nr = Refractive index of medium from which light is refracted
ni = 1.361
nr = 1.333
, θr = 90° ( Critical Angle is reffered to as Angle of Incidence at refracted angle of 90°) (θi = θc)
(ni)/(nr) = Sin (θr) / Sin (θi)
1.361/ 1.333 = Sin (90°)/ Sin( θc)
1.021= 0.894/ Sin( θc)
Sin( θc)= (0.9794
θc = Sin⁻¹ 0.9794)
θc = 78.35°
M = 10kg
P = 40 kg.m/s
V= 4m/s
Formula v = p/m
V= p/m
=4okg.m/s / 10kg
=4m/s
Hard question thx for the points give me brainlest points plz
The spiral structure of the milky way can be explained by long lived quasi-static density waves<em>, </em><em>according to the lin-shu hypothesis. </em>Curiously, the waves of higher density gas and stars (seen as spiral arms) appear to remain static as stars move around the galaxy. This explained by assuming that the gravitational disturbances cause by the 'clumping' material in the arms does not affect the gravitational field of the galaxy as whole and is therefore negligible.
source: Astrophysicist
Wassily Kandinsky invented abstract geometry :) have a good week
