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nydimaria [60]
3 years ago
15

Write y=-5/8x+3 in standard form using integers?

Mathematics
1 answer:
Ivenika [448]3 years ago
6 0

Answer:

standard form of given equation is 5x - 8y = -3

Step-by-step explanation:

y= \frac{5}{8}x + 3

Standard form of linear equation is Ax + By = C

First we remove the denominator 8

We multiply the whole equation by 8

So equation becomes

8y = 5x + 3

Now we move 5x to the left hand side, we subtract 5x on both sides

-5x + 8y = 3

Now we remove the negative side from -5x  by dividing the whole equation by -1

5x - 8y = -3


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marysya [2.9K]
Just put the coefients in to a matrix

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divide 2nd row by -3
\left[\begin{array}{ccc}1&0&-3|-14\\1&0&0|-2\\0&1&0|-3\end{array}\right]
mulstiply 2nd row by -1 and add to 1st row
\left[\begin{array}{ccc}0&0&-3|-12\\1&0&0|-2\\0&1&0|-3\end{array}\right]
divide 1st row by -3
\left[\begin{array}{ccc}0&0&1|4\\1&0&0|-2\\0&1&0|-3\end{array}\right]

rerange
\left[\begin{array}{ccc}1&0&0|-2\\0&1&0|-3\\0&0&1| 4\end{array}\right]

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