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nydimaria [60]
3 years ago
15

Write y=-5/8x+3 in standard form using integers?

Mathematics
1 answer:
Ivenika [448]3 years ago
6 0

Answer:

standard form of given equation is 5x - 8y = -3

Step-by-step explanation:

y= \frac{5}{8}x + 3

Standard form of linear equation is Ax + By = C

First we remove the denominator 8

We multiply the whole equation by 8

So equation becomes

8y = 5x + 3

Now we move 5x to the left hand side, we subtract 5x on both sides

-5x + 8y = 3

Now we remove the negative side from -5x  by dividing the whole equation by -1

5x - 8y = -3


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Step-by-step explanation:

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Students get a 15% discount off the original prices at the Everything Fluorescent store during its back to school sale. Find the
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The discount is $1.19 unless you have to round up than it is $1.20. in order to solve this problem you would set up a proportion. So your proportion would be x over 7.99 = 15 over 100. Than you would cross multiply. 7.99*15=119.85. and 100*x=100x. than u divided both sides by a 100. than x= 1.19. which 1.19 is the discount. 
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Find the percent of this number: 32% of 25 pages<br><br> Would it be 8% or 32%?
GuDViN [60]
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3 years ago
Four times a number, minus 6, is equal to three times the number, plus 8
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Answer:

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Step-by-step explanation:

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Read 2 more answers
A box contains 5 red balls, 6 white balls and 9 black balls. Two balls are drawn at
valina [46]

Answer:

P(Same)=\frac{61}{190}

Step-by-step explanation:

Given

Red = 5

White = 6

Black = 9

Required

The probability of selecting 2 same colors when the first is not replaced

The total number of ball is:

Total = 5 + 6 + 9

Total = 20

This is calculated as:

P(Same)=P(Red\ and\ Red) + P(White\ and\ White) + P(Black\ and\ Black)

So, we have:

P(Same)=\frac{n(Red)}{Total} * \frac{n(Red) - 1}{Total - 1} + \frac{n(White)}{Total} * \frac{n(White) - 1}{Total - 1}  + \frac{n(Black)}{Total} * \frac{n(Black) - 1}{Total - 1}

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

P(Same)=\frac{5}{20} * \frac{5 - 1}{20- 1} + \frac{6}{20} * \frac{6 - 1}{20- 1}  + \frac{9}{20} * \frac{9- 1}{20- 1}

P(Same)=\frac{5}{20} * \frac{4}{19} + \frac{6}{20} * \frac{5}{19}  + \frac{9}{20} * \frac{8}{19}

P(Same)=\frac{20}{380} + \frac{30}{380}  + \frac{72}{380}

P(Same)=\frac{20+30+72}{380}

P(Same)=\frac{122}{380}

P(Same)=\frac{61}{190}

4 0
3 years ago
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