1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
siniylev [52]
3 years ago
7

A chemistry student needs 10.00 g of isopropenylbenzene for an experiment. He has available 120. g of a 42.7% w/w solution of is

opropenylbenzene in carbon tetrachloride. Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution'' button. Round your answer to 3 significant digits.
Chemistry
1 answer:
Vanyuwa [196]3 years ago
3 0

<u>Answer:</u> The mass of solution that the chemistry student should use is 23.4 grams

<u>Explanation:</u>

We are given:

Available mass of isopropenylbenzene = 120. g

Amount of isopropenylbenzene needed by chemistry student = 10.00 g

42.7 % (w/w) solution of isopropenylbenzene.

This means that 42.7 grams of isopropenylbenzene is present in 100 grams of solution.

To calculate the mass of solution for given needed of isopropenylbenzene, we apply unitary method:

For 42.7 grams of isopropenylbenzene, the amount of solution needed is 100 grams

So, for 10.00 grams of isopropenylbenzene, the amount of solution needed will be = \frac{100}{42.7}\times 10=23.4g

Hence, the mass of solution that the chemistry student should use is 23.4 grams

You might be interested in
An aqueous solution of barium hydroxide is standardized by titration with a 0.102 M solution of perchloric acid. If 10.3 mL of b
Vesna [10]

<u>Answer:</u> The molarity of barium hydroxide solution is 0.118 M.

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HClO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is Ba(OH)_2

We are given:

n_1=1\\M_1=0.102M\\V_1=24.0mL\\n_2=2\\M_2=?M\\V_2=10.3mL

Putting values in above equation, we get:

1\times 0.102\times 24.0=2\times M_2\times 10.3\\\\M_2=0.118M

Hence, the molarity of Ba(OH)_2 solution will be 0.118 M.

6 0
2 years ago
What role in a factory does the cell membrane play
Vilka [71]
The plasma membrane
7 0
3 years ago
How much heat is required to warm 1.50L of water from 25.0C to 100.0C? (Assume a density of 1.0g/mL for the water.)
Masteriza [31]

<u>Answer:</u> The amount of heat required to warm given amount of water is 470.9 kJ

<u>Explanation:</u>

To calculate the mass of water, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of water = 1 g/mL

Volume of water = 1.50 L = 1500 mL    (Conversion factor:  1 L = 1000 mL)

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{1500mL}\\\\\text{Mass of water}=(1g/mL\times 1500mL)=1500g

To calculate the heat absorbed by the water, we use the equation:

q=mc\Delta T

where,

q = heat absorbed

m = mass of water = 1500 g

c = heat capacity of water = 4.186 J/g°C

\Delta T = change in temperature = T_2-T_1=(100-25)^oC=75^oC

Putting values in above equation, we get:

q=1500g\times 4.186J/g^oC\times 75^oC=470925J=470.9kJ

Hence, the amount of heat required to warm given amount of water is 470.9 kJ

6 0
3 years ago
At exactly 2:00 PM, speedy the hermit crab crawl onto a meter stick starting at the 10 cm mark. If he reaches the 60 cm mark at
kvv77 [185]

Answer:

speed=5cm/minute

Explanation:

Given at 2:00PM the hermit is at 10cm mark

Also given that the hermit reaches 60cm mark at 2:10PM

Therefore the time elapsed is  10 minutes = 10\times 60=600 seconds

the distance travelled by the hermit is 60-10=50cm=0.5m

We know that

speed=\frac{distane}{time}

speed=\frac{0.5}{600}

speed = 8.3\times 10^{-4} m/sec=5cm/minute

3 0
3 years ago
Suppose 2.8 moles of methane are allowed to react with 5 moles of oxygen.
Ronch [10]

Answer : The limiting reagent is O_2

Solution : Given,

Moles of methane = 2.8 moles

Moles of O_2 = 5 moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

CH_4+2O_2\rightarrow CO_2+2H_2O

From the balanced reaction we conclude that

As, 2 mole of O_2 react with 1 mole of CH_4

So, 5 moles of O_2 react with \frac{5}{2}=2.5 moles of CH_4

From this we conclude that, CH_4 is an excess reagent because the given moles are greater than the required moles and O_2 is a limiting reagent and it limits the formation of product.

Hence, the limiting reagent is O_2

8 0
3 years ago
Other questions:
  • The density of a solid reactant affects the rate of a reaction. <br> TRUE <br> FALSE
    13·2 answers
  • Given the chemical formula, how is this substance MOST LIKELY classified? A) atom B) compound C) both atom and compound D) neith
    7·1 answer
  • Which chemical equation is balanced?
    5·2 answers
  • High-density polyethylene may be flourinated by inducing the random substitution of Flourine atoms for hydrogen. (a) Determine t
    8·1 answer
  • Nonmetal halogen family atmoic mass 35
    6·1 answer
  • Why do amorphous solids not have a long-range order in the arrangement of their particles?
    15·2 answers
  • Which of the following molecules contains polar covalent bonds?
    15·1 answer
  • A plant would not be able to complete photosynthesis without
    8·2 answers
  • Spiral galaxies have a central core from which curved arms spiral outward. True False
    9·2 answers
  • Someone help me please
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!