A chemistry student needs 10.00 g of isopropenylbenzene for an experiment. He has available 120. g of a 42.7% w/w solution of is
1 answer:
<u>Answer:</u> The mass of solution that the chemistry student should use is 23.4 grams
<u>Explanation:</u>
We are given:
Available mass of isopropenylbenzene = 120. g
Amount of isopropenylbenzene needed by chemistry student = 10.00 g
42.7 % (w/w) solution of isopropenylbenzene.
This means that 42.7 grams of isopropenylbenzene is present in 100 grams of solution.
To calculate the mass of solution for given needed of isopropenylbenzene, we apply unitary method:
For 42.7 grams of isopropenylbenzene, the amount of solution needed is 100 grams
So, for 10.00 grams of isopropenylbenzene, the amount of solution needed will be =
Hence, the mass of solution that the chemistry student should use is 23.4 grams
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Answer:
Quantum numbers of the outermost electron in potassium:
.
.
.
- Either
.
Explanation:
Refer to the electron configuration of a potassium atom. The outermost electron in a ground-state potassium atom is in the orbital (fourth
orbital.)
The quantum number (the principal quantum number) specifies the main energy shell of an electron. This electron is in the fourth main energy shell (as seen in the number four in the orbital.) Hence,
for this electron.
The quantum number (the angular momentum quantum number) specifies the shape (
,
,
, etc.) of an electron.
for
orbitals (such as the one that contains this electron.
Quantum numbers and
specify the shape of an orbital. On the other hand, the magnetic quantum number
specifies the orientation of these orbitals in space.
However, orbitals are spherical. Regardless of the value of
, the only possible
value for electrons in
orbitals is
.
The spin quantum number distinguishes between the two electrons in an orbital. The two possible values of
are
and
. Typically, the first electron in an orbital is assigned an upward (
) spin, which corresponds to
.