Question

At exactly 2:00 PM, speedy the hermit crab crawl onto a meter stick starting at the 10 cm mark. If he reaches the 60 cm mark at exactly 2:10 PM, what is his speed?

Answer 1

Answer:

speed=5cm/minute

Explanation:

Given at 2:00PM the hermit is at 10cm mark

Also given that the hermit reaches 60cm mark at 2:10PM

Therefore the time elapsed is  10 minutes = $10\times 60=600 seconds$

the distance travelled by the hermit is 60-10=50cm=0.5m

We know that

$speed=\frac{distane}{time}$

$speed=\frac{0.5}{600}$

speed = $8.3\times 10^{-4}$ m/sec=5cm/minute