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Blababa [14]
3 years ago
12

At exactly 2:00 PM, speedy the hermit crab crawl onto a meter stick starting at the 10 cm mark. If he reaches the 60 cm mark at

exactly 2:10 PM, what is his speed?
Chemistry
1 answer:
kvv77 [185]3 years ago
3 0

Answer:

speed=5cm/minute

Explanation:

Given at 2:00PM the hermit is at 10cm mark

Also given that the hermit reaches 60cm mark at 2:10PM

Therefore the time elapsed is  10 minutes = 10\times 60=600 seconds

the distance travelled by the hermit is 60-10=50cm=0.5m

We know that

speed=\frac{distane}{time}

speed=\frac{0.5}{600}

speed = 8.3\times 10^{-4} m/sec=5cm/minute

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Two objects are brought into contact Object 1 has mass 0.76 kg, specific heat capacity 0.87) g'c and initial temperature 52.2 'C
taurus [48]

Answer:

T_F=77.4\°C

Explanation:

Hello there!

In this case, according to the given information, it turns out possible to set up the following energy equation for both objects 1 and 2:

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In terms of mass, specific heat and temperature change is:

m_1C_1(T_F-T_1)=-m_2C_2(T_F-T_2)

Now, solve for the final temperature, as follows:

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Then, plug in the masses, specific heat and temperatures to obtain:

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Yet, the values do not seem to have been given correctly in the problem, so it'll be convenient for you to recheck them.

Regards!

4 0
3 years ago
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