1. NaF, Na₂S, Na₃P, Na₂O
2. MgF₂, MgS, Mg₃P₂, MgO
3. AlF₃, Al₂S₃, AlP, Al₂O₃
<h3>Further explanation</h3>
Given
Ionic charge
Required
The formula of binary ionic compounds
Solution
Ionic compounds consisting of cations (ions +) and anions (ions -)
Ionic compounds usually consist of metal cations and non-metal anions
Metal: cation, positively charged.
Nonmetal: negatively charged
The anion cation's charge is crossed
The ionic compounds :
1. NaF, Na₂S, Na₃P, Na₂O
2. MgF₂, MgS, Mg₃P₂, MgO
3. AlF₃, Al₂S₃, AlP, Al₂O₃
Answer:
= 331.81 g
Explanation:
Molarity is calculated by the formula;
Molarity = Moles/volume in liters
Therefore;
Moles = Molarity ×Volume in liters
= 0.35 M × 1.575 L
= 0.55125 Moles
But; Molar mass of Ba3(PO4)2 is 601.93 g/mol
Thus;
Mass = 0.55125 moles × 601.93 g/mol
<u>= 331.81 g</u>
Answer:
2.77 mL of boiling water is the minimum amount which will dissolve 500 mg of phthalic acid.
Explanation:
We know from the problem that 18 g of phthalic acid are dissolved in 100 mL of water at 99 °C.
Now we devise the following reasoning:
If 18 g of phthalic acid are dissolved in 100 mL of water at 99 °C
Then 0.5 g of phthalic acid are dissolved in X mL of water at 99 °C
X = (0.5 × 100) / 18 = 2.77 mL of water
Answer:
two may be the answer (2)
