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DochEvi [55]
4 years ago
8

What is the answer please and why is this answer

Chemistry
1 answer:
Korolek [52]4 years ago
3 0
C. Between ages 2 and 3
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. KMnO4 oxidizes ethyl benzene to benzoic acid. If this reaction generally results in a 40 % experimental yield, how many grams
lyudmila [28]

Answer:

530.835 g

Explanation:

First we convert 244 g of benzoic acid (C₇H₆O₂) to moles, using its molar mass:

  • 244 g benzoic acid ÷ 122.12 g/mol = 2.00 moles benzoic acid

Theoretically,<em> one mol of ethyl benzene would produce one mol of benzoic acid</em>. But the experimental yield tells us that one mol of ethyl benzene will produce only 0.4 moles of benzoic acid.

With the above information in mind we convert 2.00 moles of benzoic acid into moles of ethyl benzene:

  • 2.00 moles benzoic acid * \frac{1molEthylBenzene}{0.4molBenzoicAcid} = 5.00 moles ethyl benzene

Finally we <u>convert moles of ethyl benzene </u>(C₈H₁₀)<u> into grams</u>, using its <em>molar mass</em>:

  • 5.00 moles ethyl benzene * 106.167 g/mol = 530.835 g ethyl benzene
7 0
3 years ago
A 700.0 mL gas sample at STP is compressed to a volume of 200.0 mL, and the temperature is increased to 30.0°C. What is the new
dolphi86 [110]

Answer: The new pressure of the gas in Pa is 388462

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas at STP = 10^5Pa

P_2 = final pressure of gas = ?

V_1 = initial volume of gas = 700.0 ml

V_2 = final volume of gas = 200.0 ml

T_1 = initial temperature of gas = 273 K

T_2 = final temperature of gas = 30^oC=273+30=303K

Now put all the given values in the above equation, we get:

\frac{10^5\times 700.0ml}{273K}=\frac{P_2\times 200.0ml}{303K}

P_2=388462Pa

The new pressure of the gas in Pa is 388462

6 0
3 years ago
WILL GIVE 15 POINTS FOR ANSWER WITH EXPLANATION PLEASE HELP!!!
VashaNatasha [74]
The crudos is h2o combined with c3o
6 0
3 years ago
Sodium metal is sometimes used as a cooling agent in heat exchange units because of its relatively high molar heat capacity of 2
IgorC [24]

Answer:

The specific heat of sodium is 1,23J/g°C

Explanation:

Using the atomic weight of sodium (23g/mol) and the atomic weight definition, we have that each mole of the substance has 23 grams of sodium.

starting from this, we use the atomic weight of sodium to convert the units from J / mol ° C to J / g ° C

28,2 \frac{J}{mol C} x \frac{1mol}{23g} = 1,23 J/g C

4 0
3 years ago
Give the formulas for the ionic compounds made of the following ions:
mezya [45]
ScBr3, K2O, CaI2, Cr2S3, RbF, MgO, K3N, SrF2, and Al2S3. The only thing you need to do is to ensure every ionic compound has a total valence of zero. Four the last four, you need to know usually valence of these ions.
5 0
4 years ago
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