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vichka [17]
3 years ago
8

ABCD is a trapezoid (AD∥ BC). BC = 5 cm, m∠ACD = m∠ABC = 90°, m∠BAC = 30°. Find the length of AD (the picture is not drawn to sc

ale).

Mathematics
1 answer:
lana [24]3 years ago
4 0

Answer:

AD=20\ cm  

Step-by-step explanation:

step 1

Find the length of AC

In the right triangle ABC

sin(

we have

m

BC=5\ cm

substitute and solve for AC

sin(30\°)=\frac{5}{AC}

0.5=\frac{5}{AC}  

AC=10\ cm          

step 2

Find the length side AD

In the right triangle ACD

cos(

we have

m

AC=10\ cm

substitute and solve for AD

cos(60\°)=\frac{10}{AD}

0.5=\frac{10}{AD}

AD=20\ cm  

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