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Viktor [21]
3 years ago
15

A certain shade of blue has a frequency of 7.08×1014 Hz. What is the energy of exactly one photon of this light? Planck's consta

nt ℎ=6.626×10−34 J⋅s.
Chemistry
1 answer:
Anvisha [2.4K]3 years ago
8 0

Answer:

We have the final answer as

4.69 \times  {10}^{ - 19}  \:  \:  J

Explanation:

To find the energy of a photon of this light we use the formula

<h3>E = hf</h3>

where

E is the energy

f is the frequency

h is the Planck's constant which is

6.626 × 10-³⁴ Js

From the question

f = 7.08×10¹⁴ Hz

We have

E = 7.08×10¹⁴ × 6.626 × 10-³⁴

We have the final answer as

4.69 \times  {10}^{ - 19}  \:  \:  J

Hope this helps you

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