Question

A certain shade of blue has a frequency of 7.08×1014 Hz. What is the energy of exactly one photon of this light? Planck's constant ℎ=6.626×10−34 J⋅s.

Answer 1

Answer:

We have the final answer as

$4.69 \times {10}^{ - 19} \: \: J$

Explanation:

To find the energy of a photon of this light we use the formula

E = hf

where

E is the energy

f is the frequency

h is the Planck's constant which is

6.626 × 10-³⁴ Js

From the question

f = 7.08×10¹⁴ Hz

We have

E = 7.08×10¹⁴ × 6.626 × 10-³⁴

We have the final answer as

$4.69 \times {10}^{ - 19} \: \: J$

Hope this helps you