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LekaFEV [45]
3 years ago
15

The law of conversion states that mass is never created or destroyed. Explain how this law requires all chemical equations to be

balanced.
Chemistry
1 answer:
ikadub [295]3 years ago
3 0

Answer:

See Explanation

Explanation:

The Law of Conservation of Matter as applied to chemical reactions says that matter is neither created nor distroyed, only changed in form. This implies that the mass of substances going into a reaction process must equal the mass of products generated during the reaction process.

Empirically,

∑ mass reactants = ∑ mass products

One can test this idea after balancing a chemical equation by determining the sum of formula weights of reactants and products; then compare. If reaction was properly balanced, the total mass reactants = total mass of products.

Example:

Combustion of Methane =>  CH₄(g) + 2O₂(g)   =>  CO₂(g) + 2H₂O(l)

Equation Weights =>             16amu + 64amu <=> 44amu +  36amu

Mass Reactants = Mass Products  => 80amu <=> 80amu.

__________________

*amu = atomic mass units => sum of atomic weights of elements

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De acuerdo con la Ley de la Conservación de la Materia postulada por Lavoisier, ¿cuál ecuación química está balanceada? A C2H5OH
olya-2409 [2.1K]

Answer:

C C2H5OH(l) + 3O2(g) → 2CO2 + 3H2O

Explanation:

La ley de conservación de la materia implica que en una reacción química los átomos en los reactivos son iguales a la cantidad de átomos en los productos:

A C2H5OH(l) + O2(g) → CO2 + H2O

En los reactivos hay dos átomos de carbono pero en los productos solo 1. De esta manera, no cumple la ley de conservación.

B C2H5OH(l) + O2(g) → 2CO2 + H2O

En los reactivos hay 6 átomos de hidrógeno pero en los productos solo 2. No cumple la ley de conservación.

C C2H5OH(l) + 3O2(g) → 2CO2 + 3H2O

En los reactivos y productos hay: 2 átomos de carbono, 6 átomos de hidrógeno y 7 átomos de oxígeno. Cumple la ley de conservación.

D C2H5OH(l) + O2(g) → 2CO2 + 3H2O

En los reactivos hay 3 átomos de oxígeno y en los productos 7. No cumple la ley de conservación.

E 2C2H5OH(l) + 3O2(g) → 2CO2 + 3H2O

En los reactivos hay 4 átomos de carbono y en los productos solo dos. No cumple la ley de conservación.

6 0
3 years ago
Which type of reactions form salts?
Marysya12 [62]

Answer:

Neutralization reactions

Explanation:

A neutralization reaction is a reaction between an acid and a base. Products of this type of reaction is water and a salt. The pH of the salt product would depend on how strong or weak the base and acid would be when they react with each other. Although the characteristics of bases and acids are practically polar opposites, when combined, they cancel each other our producing a neutralized product.

6 0
3 years ago
A beam of light passes though a liquid in a test tube without scattering. Which type of mixture is most likely in the test tube?
butalik [34]
The answer would be letter C - solution.

A mixture should be homogeneous for a light not to be scattered. This is because particles are distributed evenly throughout the mixture which allows light to pass directly. In your choices, the solution allows a  beam of light to pass through a liquid in a test tube without scattering.
6 0
3 years ago
Read 2 more answers
If one mole of a substance has a mass of 56.0 g, what is the mass of 11 nanomoles of the substance? Express your answer in nanog
9966 [12]

Answer:

616,0 ng is the right answer.

Explanation:

You should know that 1 mole = 1 .10^9 nanomoles

Get the rule of three.

1 .10^9 nanomoles ...................... 56.0 gr

11 nanomoles .....................

(11 x 56) / 1 .10^9 nanomoles = 6.16 x 10^-7 gr

Let's convert

6.16 x 10^-7 gr x 1 .10^9 = 616 ngr

8 0
3 years ago
2. Extract the relevant information from the question: NaOH V = 30 mL , M = 0.10 M HCl V = 25.0 mL, M = ?
Andrei [34K]

Answer:

0.12M

Explanation:

A balanced equation for the reaction will go a great deal in obtaining our desired result. So, let us write a balanced equation for the reaction

HCl + NaOH —> NaCl + H2O

From the above equation,

nA (mole of the acid) = 1

nB (mole of the base) = 1

Data obtained from the question include:

Vb (volume of the base) = 30mL

Mb (Molarity of the base) = 0.1M

Va (volume of the acid) = 25mL

Ma (Molarity of the acid) =?

The molarity of the acid can be obtained as follow:

MaVa/MbVb = nA/nB

Ma x 25/ 0.1 x 30 = 1

Cross multiply to express in linear form

Ma x 25 = 0.1 x 30

Divide both side by 25

Ma = (0.1 x 30) / 25

Ma = 0.12M

The molarity of the acid is 0.12M

5 0
3 years ago
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