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malfutka [58]
4 years ago
13

A projectile is fired from a gun near the surface of earth. the initial velocity of the projectile has a vertical component of 9

8 meters per second and a horizontal component of 49 meters per second. how long will it take the projectile to reach the highest point in its path?
Physics
2 answers:
nadezda [96]4 years ago
8 0
The gravitational acceleration experienced by the bullet due to the earth's gravitational force is approximately equals to 9.81 m/s^2

At maximum point of height, vertical component of velocity equals to zero because it experiences a pause momentarily before coming back down.

Since -acceleration=(Final velocity-initial velocity) divided by time. Taking upwards to be positive, time taken= 10s
Serga [27]4 years ago
7 0

Answer:

10 seconds

Explanation:

There are many formulas that can be used to calculate time taken, or final velocity, or initial velocity, etc.

However, the easiest formula to use in this situation would be:

v = u + at (where v= final velocity; u= initial velocity; a= acceleration; t= time)

At the bullet's highest point, it will not have any vertical velocity, and since we are trying to find the time it takes to reach the highest point, we take the final velocity as zero.

Initial velocity was given as 98 m/s in the vertical direction.

Acceleration due to gravity is -9,8 m/s² (negative due to taking the up direction as positive).

Plugging in the values:

t = (v-u) / a

t = (0-98 m/s) / -9,8 m/s²

t = 10 seconds

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Describe a solar eclipse. Be sure to include the positions of the sun, moon, and earth.
Alex777 [14]
It’s the type of eclipse that occurred when the moon passes between the sun and earth, and when the moon fully or partially blocks the sun.
7 0
3 years ago
You place a point charge q = -4.00 nC a distance of 9.00 cm from an infinitely long, thin wire that has linear charge density 3.
valentinak56 [21]

Answer:

F=6\times 10^{-7}\ N

Explanation:

Given:

  • quantity of point charge, q=-4\times 10^{-9}\ C
  • radial distance from the linear charge, r=0.09\ m
  • linear charge density, \lambda=3\times 10^{-9}\ C.m^{-1}

<u>We know that the electric field by the linear charge  is given as:</u>

E=\frac{\lambda}{2\pi.\epsilon_0.r}

E=\frac{1}{2}\times 9\times 10^9\times \frac{3\times10^{-9}}{0.09}

E=150\ N.C^{-1}

<u>Now the force on the given charge can be given as:</u>

F=E.q

F=150\times 4\times 10^{-9}

F=6\times 10^{-7}\ N

3 0
4 years ago
Explain this quote "ambition beats genius 99% of the time. "
klasskru [66]

Answer:

The idea that hard work is the most important aspect of new inventions existed before Edison gave his quote, however.

The idea behind this quote is that it is easy to have a good idea, or a creative insight. However, to follow through with that idea, and turn it into a reality, takes a level of patience and dedication that few people have.

Explanation:

7 0
3 years ago
Read 2 more answers
PWEESE HELP ME WIT MY QUIZ
kaheart [24]
I believe it is acceleration
7 0
3 years ago
Read 2 more answers
Jaclyn plays singles for South's varsity tennis team. During the match against North, Jaclyn won the sudden death tiebreaker poi
Nataly [62]

Answer

given,

mass of ball, m = 57.5 g = 0.0575 kg

velocity of ball northward,v = 26.7 m/s

mass of racket, M = 331 g = 0.331 Kg

velocity of the ball after collision,v' = 29.5 m/s

a) momentum of ball before collision

   P₁ = m v

   P₁ = 0.0575 x 26.7

   P₁ = 1.535 kg.m/s

b) momentum of ball after collision

   P₂ = m v'

   P₂ = 0.0575 x (-29.5)

   P₂ = -1.696 kg.m/s

c) change in momentum

    Δ P = P₂ - P₁

    Δ P = -1.696 -1.535

    Δ P = -3.231 kg.m/s

d) using conservation of momentum

  initial speed of racket = 0 m/s

  M u + m v = Mu' + m v

  M x 0 + 0.0575 x 26.7 = 0.331 x u' + 0.0575 x (-29.5)

  0.331 u' = 3.232

     u' = 9.76 m/s

change in velocity of the racket is equal to 9.76 m/s

5 0
3 years ago
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