Question

A projectile is fired from a gun near the surface of earth. the initial velocity of the projectile has a vertical component of 98 meters per second and a horizontal component of 49 meters per second. how long will it take the projectile to reach the highest point in its path?

Answer 1

The gravitational acceleration experienced by the bullet due to the earth's gravitational force is approximately equals to 9.81 m/s^2

At maximum point of height, vertical component of velocity equals to zero because it experiences a pause momentarily before coming back down.

Since -acceleration=(Final velocity-initial velocity) divided by time. Taking upwards to be positive, time taken= 10s

Answer 2

Answer:

10 seconds

Explanation:

There are many formulas that can be used to calculate time taken, or final velocity, or initial velocity, etc.

However, the easiest formula to use in this situation would be:

v = u + at (where v= final velocity; u= initial velocity; a= acceleration; t= time)

At the bullet's highest point, it will not have any vertical velocity, and since we are trying to find the time it takes to reach the highest point, we take the final velocity as zero.

Initial velocity was given as 98 m/s in the vertical direction.

Acceleration due to gravity is -9,8 m/s² (negative due to taking the up direction as positive).

Plugging in the values:

t = (v-u) / a

t = (0-98 m/s) / -9,8 m/s²

t = 10 seconds