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Dvinal [7]
3 years ago
8

What is the perimeter and area of a rectangle if length is (2x+3) and width is (4x+6). Please show your answer !!

Mathematics
1 answer:
Bond [772]3 years ago
3 0
To find the area of a rectangle, the formula is length*width
(2x+3)(4x+6)
So you distribute it.
8x^2+12x+12x+18
Combine like terms.
8x^2+24x+18
The factor it out.
(8x^2+12x) (12x+18)
4x(2x+3) 6(2x+3)
(4x+6) (2x+3)

So the answer is:
2(x+3) (2x+3)

I hope this has helped. Have a great day/night!
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Translate the scenario below to a linear equation, then solve.
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Answer:  x + 2x + x-40 = 180

First angle= 55º

Second angle= 110º

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​Step-by-step explanation:  The sum of the angles of a triangle is 180º

Take the values given and  use x as the unknown first angle. then create terms for the other two angles based on that:

The second angle of a triangle is double the first angle  becomes 2x

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x + 2x + x-40 = 180  Solve by adding like terms . x + 2x + x = 4x

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4x + 40 -40 = 180 + 40   becomes  

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4x/4 = 220/4

x = 55   This is the first angle. Substitute 55 for the  "x" in the original terms

2(55) = 110   The second angle

(55) -40 = 15   the third angle

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