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3 years ago

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A simple circuit with a battery connected to a buzzer by electrical wires is placed on a table. When the buzzer sounds, the tabl

e begins to ratte. Which form of energy makes the table rattle?
chemical
ОО
electrical
heat
mechanical

1 answer:

Ainat [17]3 years ago

7 0

Answer:

Mechanical

Explanation:

mechanical energy:

energy that an object has

because of its motion or

position

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Some acids are capable of drawing water out of an object. This process is called _____.

vagabundo [1.1K]

Some acids are capable of drawing water out of an object. This process is called dehydration.

Hope this helped!

7 0

4 years ago

At a certain temperature, 0.3411 0.3411 mol of N 2 N2 and 1.661 1.661 mol of H 2 H2 are placed in a 2.50 2.50 L container. N 2 (

Sveta_85 [38]

<u>Answer:</u> The equilibrium constant for the above reaction is 1.31

<u>Explanation:</u>

We are given:

Initial moles of nitrogen gas = 0.3411 moles

Initial moles of hydrogen gas = 1.661 moles

Equilibrium moles of nitrogen gas = 0.2001 moles

For the given chemical reaction:

$N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)$

<u>Initial:</u> 0.3411 1.661

<u>At eqllm:</u> 0.3411-x 1.661-3x 2x

Evaluating for 'x', we get:

$\Rightarrow (0.3411-x)=0.2001\\\\\Rightarrow x=0.3411-0.2001=0.141$

Volume of the container = 2.50 L

The expression of $K_c$ for the above equation follows:

$K_c=\frac{[NH_3]^2}{[N_2]\times [H_2]^3}$

We are given:

$[NH_3]=\frac{2\times 0.141}{2.50}=0.1128M$

$[N_2]=\frac{0.2001}{2.5}=0.08004M$

$[H_2]=\frac{1.661-(3\times 0.141)}{2.5}=0.4952M$

Putting values in above expression, we get:

$K_c=\frac{(0.1128)^2}{0.08004\times (0.4952)^3}\\\\K_c=1.31$

Hence, the equilibrium constant for the above reaction is 1.31

5 0

3 years ago

Consider the following reaction: 2 Bi(s) + 3 Cl2(g) → 2 BiCl3(s)

Mandarinka [93]

Taking into account the reaction stoichiometry, 1.119 grams of chlorine gas are required to produce 3.32 grams of bismuth chloride is produced.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

2 Bi + 3 Cl₂ → 2 BiCl₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Bi: 2 moles
Cl₂: 3 moles
BiCl₃: 2 moles

The molar mass of the compounds is:

Bi: 209 g/mole
Cl₂: 70.90 g/mole
BiCl₃: 315.45 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Bi: 2 moles ×209 g/mole=418 g

Cl₂: 3 moles ×70.90 g/mole= 212.7 g

BiCl₃: 2 moles ×315.45 g/mole= 630.9 g

<h3>Mass of Cl₂ required</h3>

The following rule of three can be applied: If by reaction stoichiometry 630.9 grams of BiCl₃ are formed by 212.7 grams of Cl₂, 3.32 grams of BiCl₃ are formed by how much mass of Cl₂?

$mass of Cl_{2} =\frac{3.32 grams of BiCl_{3}x212.7 grams of Cl_{2} }{630.9 grams of BiCl_{3}}$

<u><em>mass of Cl₂= 1.119 grams</em></u>

Finally, 1.119 grams of chlorine gas are required to produce 3.32 grams of bismuth chloride is produced.

Learn more about the reaction stoichiometry:

<u>brainly.com/question/24741074</u>

<u>brainly.com/question/24653699</u>

5 0

3 years ago

When the enthalpy of the reaction is provided, it is always in the context of moles; i.e., ΔHrxn=+252.8 kJ when two moles of CH3

Morgarella [4.7K]

<u>Answer:</u> The balanced chemical equation is written below.

<u>Explanation:</u>

There are 2 types of chemical reaction classified on the basis of heat change:

<u>Endothermic reactions </u>: They are the reactions in which energy of products is more than the energy of the reactants. For these reactions, energy is absorbed by the system. The $\Delta H$ comes out to be positive and is written on the reactants side.
<u>Exothermic reactions:</u> They are the reactions in which energy of reactants is more than the energy of the products. For these reactions, energy is released by the system. The $\Delta H$ comes out to be negative and is written on the product side.

We are given:

Moles of methanol = 2 moles

Moles of methane = 2 moles

Moles of oxygen gas = 1 mole

$\Delta H_{rxn}=+252.8kJ$

The chemical equation follows:

$2CH_3OH+252.8kJ\rightarrow 2CH_4+O_2$

Hence, the balanced chemical equation is written above.

4 0

3 years ago

2. A solution is made by adding 1.23 mol of KCl to 1000.0 g of water. Assume that the

ladessa [460]

Answer:

a. 74.55 g/mol.

b. 91.70 g.

c. 8.40%.

d. 1.23 mol/L.

Explanation:

<em>a. Calculate the formula weight of KCl.</em>

∵ Formula weight of KCl = atomic weight of K + atomic weight of Cl

atomic weight of K = 39.098 g/mol, atomic weight of Cl = 35.45 g/mol.

∴ Formula weight of KCl = atomic weight of K + atomic weight of Cl = 39.098 g/mol + 35.45 g/mol = 74.548 g/mol ≅ 74.55 g/mol.

<em>b. Calculate the mass of KCl in grams.</em>

we can use the relation:

<em>no. of moles (n) = mass/molar mass.</em>

∴ mass of KCl = n*molar mass = (1.23 mol)*(74.55 g/mol) = 91.69 g ≅ 91.70 g.

<em>c. Calculate the percent by mass of KCl in this solution.</em>

The mass % of KCl = (mass of KCl/mass of the solution) * 100.

mass of KCl = 91.70 g,

mass of the solution = 1000.0 g of water + 91.70 g of KCl = 1091.70 g.

∴ The mass % of KCl = (91.70 g/1091.70 g)*100 = 8.399% ≅ 8.40%.

<em>d. Calculate the molarity of the solution.</em>

Molarity is the no. of moles of solute per 1.0 L of the solution.

<em>M = (no. of moles of KCl)/(Volume of the solution (L))</em>

no. of moles of KCl = 1.23 mol,

Volume of the solution = mass of water / density of water = (1000.0 g)/(1.00 g/mL) = 1000.0 mL = 1.0 L.

M = (1.23 mol)/(1.0 L) = 1.23 mol/L.

3 0

4 years ago