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steposvetlana [31]
4 years ago
12

The resistance of a wire is not dependent on

Physics
1 answer:
Komok [63]4 years ago
3 0

d. Current

It is opposing

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5. How much does a 20 m x 10 m x 8 m swimming pool filled with water weigh? Assume that water has a density of 62 kg/m'.​
Nookie1986 [14]

Explanation:

First of all we calculate the volume which is 20m×10m×8m= 1600m^3 and then multiply the density by the volume to get the mass which will equal to 99200kg therefore the weight will be

<em><u>Weight</u></em>

mass × acceleration due to gravity

=99200kg × 10m^s^2

=992000N

7 0
3 years ago
A pitcher delivers a fast ball with a velocity of 43 m/s to the south. the batter hits the ball and gives it a velocity of 51 m/
hoa [83]
Assuming north as positive direction, the initial and final velocities of the ball are:
v_i=-43 m/s (with negative sign since it is due south)
v_f=+51 m/s
the time taken is t=1.0 ms=0.001 s, so the average acceleration of the ball is given by
a= \frac{v_f-v_i}{t}= \frac{51 m/s-(-43 m/s)}{0.001 s}=9.4 \cdot 10^4 m/s^2
And the positive sign tells us the direction of the acceleration is north.
4 0
3 years ago
Which of the following correctly describe electric field lines?
Xelga [282]

-- Electric field lines DO never cross.  <em>(A) </em>

-- Electric field lines that are close together DO indicate a stronger electric field. <em>(B) </em>

-- Electric field lines DO not affect the charge that created them.  <em>(C)</em>

-- Electric field lines DON'T begin on north poles and end on south poles.  North and South "poles" are the way we talk about magnets, not electric charges.

6 0
3 years ago
Read 2 more answers
Can someone please help me with this
pentagon [3]
The key principle is that crank length, just like frame size, should be proportional to the rider height and then modified to what fits the individual. There are 4 charts, two for the upright position and two for the aero position, depending upon how you race.
4 0
2 years ago
uniform electric field exists between two parallel plates separated by 2.0 cm. The intensity of the field is 15 kN/C. What is th
adoni [48]

Answer:

potential difference V= 300 volts

Explanation:

Given:

d= 2.0 cm = 0.02m

E = 15 kN/C = 15 × 10³ N/C

For a uniform field between two plates, the Electric Filed Intensity (E) is proportional to the potential difference (V) and inversely  proportional to distance between the plates.

E= V/d

⇒ V= E×d = 15 × 10³ N/C × 0.02 m = 300 volts  (∴1 Nm/C = 1 J/C= 1 volts)

7 0
3 years ago
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