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belka [17]
2 years ago
9

A 12.0-g bullet is fired horizontally into a 112-g wooden block that is initially at rest on a frictionless horizontal surface a

nd connected to a spring having spring constant 149 N/m. The bullet becomes embedded in the block. If the bullet-block system compresses the spring by a maximum of 83.5 cm, what was the speed of the bullet at impact with the block
Physics
1 answer:
sergiy2304 [10]2 years ago
7 0
The speed would be in a decimal? Or do you want it in a fraction?
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A particular planet has a moment of inertia of 8.26 × 1036 kg⋅m2 and a mass of 6.54 × 1022 kg. Based on these values, what is th
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Answer: Correct answer is B = 1.776933×10^{7}

Explanation:

Given :

Moment of inertia I = 8.26×10^{36} kgm^{2}

Mass of planet m = 6.54×10^{22} kg

Also, Planet is solid sphere so that, Moment of inertia is I = \frac{2}{5} mR^{2} =0.4mR^{2}

Where R is radius of planet

Putting into calculation

We get,

I = \frac{2}{5} mR^{2}

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R =  1.776933×10^{7}

Thus, Correct answer is B = 1.776933×10^{7}

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Answer:

See the explanation for the answer.

Explanation:

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I think that these answers are correct. I'm sorry if they aren't, I tried my best with the assignment.

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