Transverse wave, motion in which all points on a wave oscillate along paths at right angles to the direction of the wave's advance. Surface ripples on water, seismic S (secondary) waves, and electromagnetic (e.g., radio and light) waves are examples of transverse waves.
Answer:
Explanation:
This question appears incomplete but can however still b answered.
The purpose of the experiment is <u>to test the effectiveness of the new sunscreen</u>.
An independent variable is the variable that is changed (directly or indirectly) during the course of an experiment. The independent variable here are the <u>sunscreen</u>.
A dependent variable is the variable that is been tested in the course of the experiment. The dependent variable here is the <u>redness of the skin</u>.
The first group here (this could be in the missing part of the question, hence response not certain) is the control group. The control group consists of the arms sprayed with the leading/old sunscreen formula.
The second group is the test group. It consists of the arms sprayed with the new sunscreen formula.
The factors that are kept constant (or control variable) are <u>the duration under the sun (4 hrs)</u> and <u>the participants' arms used</u>.
The <u>test group is the second group</u> while <u>the group used for comparison</u> (to be sure the new sunscreen is more effective) <u>is the first group</u>.
Answer:
Learning is essential to our existence. Just like food nourishes our bodies, information and continued learning nourishes our minds. ... Today, continuous learning forms a necessary part in acquiring critical thinking skills and discovering new ways of relating to people from different cultures.
Explanation:
Learning is essential to our existence. Just like food nourishes our bodies, information and continued learning nourishes our minds. ... Today, continuous learning forms a necessary part in acquiring critical thinking skills and discovering new ways of relating to people from different cultures.
Answer:
Explanation:
Combustion reaction is given below,
C₂H₅OH(l) + 3O₂(g) ⇒ 2CO₂(g) + 3H₂O(g)
Provided that such a combustion has a normal enthalpy,
ΔH°rxn = -1270 kJ/mol
That would be 1 mol reacting to release of ethanol,
⇒ -1270 kJ of heat
Now,
0.383 Ethanol mol responds to release or unlock,
(c) Determine the final temperature of the air in the room after the combustion.
Given that :
specific heat c = 1.005 J/(g. °C)
m = 5.56 ×10⁴ g
Using the relation:
q = mcΔT
- 486.34 = 5.56 ×10⁴ × 1.005 × ΔT
ΔT= (486.34 × 1000 )/5.56×10⁴ × 1.005
ΔT= 836.88 °C
ΔT= T₂ - T₁
T₂ = ΔT + T₁
T₂ = 836.88 °C + 21.7°C
T₂ = 858.58 °C
Therefore, the final temperature of the air in the room after combustion is 858.58 °C
Answer:
9.606 g
Explanation:
Step 1: Write the balanced combustion reaction
C₂H₆O(l) + 3 O₂(g) → 2 CO₂(g) + 3 H₂O(g)
Step 2: Calculate the moles corresponding to 11.27 g of H₂O
The molar mass of H₂O is 18.02 /mol.
11.27 g × (1 mol/18.02 g) = 0.6254 mol
Step 3: Calculate the moles of C₂H₆O that formed 0.6254 moles of H₂O
The molar ratio of C₂H₆O to H₂O is 1:3. The moles of C₂H₆O are 1/3 × 0.6254 mol = 0.2085 mol
Step 4: Calculate the mass corresponding to 0.2085 moles of C₂H₆O
The molar mass of C₂H₆O is 46.07 g/mol.
0.2085 mol × 46.07 g/mol = 9.606 g