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Kobotan [32]
2 years ago
12

10

Physics
2 answers:
tatuchka [14]2 years ago
8 0

Answer:

B. 1.7A

Explanation:

R = Resistance

I = Current

V = Voltage (potential difference)

22+4.5 = 26.5

45/26.6= 1.698

Round 1.698 to the nearest hundredth: 1.7

The current of the circuit is 1.7

Paul [167]2 years ago
4 0

Answer:

According to Ohm's law ,

V = IR

where ,

V = Potential difference

I = Current flowing

R = Total resistance

here ,

R _{t} = 22Ω + 4.5Ω = 26.5Ω

( since , the resistors are connected in series )

Using Ohm's Law ,

45 = I(26.5) \\  I =  \frac{45}{26.5}  \\  \\ I = 2.5A \: (approx.)

Therefore , option ( 1 ) is correct.

hope helpful~

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Given:

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- Radius of the cylinder R = 0.44 m

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- The initial speed of cylinder w_i = 0 rad/s

- The initial speed of particle V_pi = 3.3 m/s

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- Mass moment of inertia of a particle around an axis I_p = mR^2

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                                     L_i = L_f

- Initially, the particle is at edge at a distance R from center of cylinder axis with a velocity V_pi = 3.3 m/s contributing to the initial angular momentum of the system by:

                                    L_(p,i) = m*V_pi*R

                                    L_(p,i) = 3.6*3.3*0.44

                                    L_(p,i) = 5.2272 kgm^2 /s

- While the cylinder was initially stationary w_i = 0:

                                    L_(c,i) = I*w_i

                                    L_(c,i) = 0.5*M*R^2*0

                                    L_(c,i) = 0 kgm^2 /s

The initial momentum of the system is L_i:

                                    L_i = L_(p,i) + L_(c,i)

                                    L_i = 5.2272 + 0

                                    L_i = 5.2272 kg-m^2/s

- After, the particle attaches itself to the cylinder, the mass and its distribution around the axis has been disturbed - requires an equivalent Inertia for the entire one body I_equivalent. The final angular momentum of the particle is as follows:

                                   L_(p,f) = I_p*w_f

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                                   L_(c,f) = I_c*w_f

- Note, the final angular velocity w_f are same for both particle and cylinder. Every particle on a singular incompressible (rigid) body rotates at the same angular velocity around a fixed axis.

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                                  L_i = L_f

                                  5.2272 = w_f*(I_p + I_c)

                                  w_f =  5.2272/ R^2*(m + 0.5M)

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                                  w_f =  5.2272/ 0.44^2*(3.6 + 0.5*45)

                                  w_f =  5.2272/ 5.05296

                                  w_f = 1.0345 rad/s

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