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Ronch [10]
3 years ago
14

which of these best dscribes Earth's mantle? A. most dense layer, consists of the outer and inner parts B. thinnest under the oc

eans and thickest under continents C. middle layer, density increases with depth as pressure increases D. least dense layer overall, consists of two layers of different thickness
Physics
1 answer:
stich3 [128]3 years ago
6 0

C. middle layer, density increases with depth as pressure increases

Explanation:

The mantle is the middle layer of the earth. It's density increases with depth as pressure increases.

  • Based on the compositional division of the earth, our blue planet is divided into crust, mantle and the core.
  • The crust is the lightest and the outermost layer of the earth.
  • The mantle is the middle layer. Its density lies between that of the core and crust.
  • The mantle is the largest layer and density increases with depth here.
  • The core is a metallic ball. It is the most dense part of the earth.

Learn more:

Mantle brainly.com/question/10758534

#learnwithBrainly

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Zinaida [17]

Answer:

Decreases by $3.6 \times 10^{-3}$ times

Explanation:

The intensity of a sound is defined as the energy of the sound that is flowing in an unit time through the unit area which is in the direction that is perpendicular to the direction of the sound waves movement.

The intensity of energy is described by the inverse square law. It states that the intensity varies inversely with the distance square of the distance.

In other words, the sound intensity decreases as inversely proportional to the squared of the distance.  i.e. $\frac{1}{r^2}$

In the context when the distance was 3 m, the intensity of the sound was = $\frac{1}{9}$

But when the distance became 6 cm or 0.06 m, the sound intensity decreases by =  $\frac{1}{0.06^2}$

                       = $3.6 \times 10^{-3}$ times

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3 years ago
A gas has an initial volume of 168 cm3 at a temperature of 255 K and a pressure of 1.6 atm. The pressure of the gas decreases to
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3 years ago
Light of wavelength 476.1 nm falls on two slits spaced 0.29 mm apart. What is the required distance from the slits to the screen
stich3 [128]

Answer:

The distance is D  =  2.6 \ m

Explanation:

From the question we are told that

    The wavelength of the light is  \lambda  =  476.1 \ nm  =  476.1 *10^{-9} \ m

      The  distance between the slit is  d =  0.29 \  mm  =  0.29 *10^{-3} \ m

       The  between the first and second dark fringes is  y =  4.2 \ mm  =  4.2 *10^{-3} \ m

Generally  fringe width is mathematically represented as

       y  =  \frac{\lambda * D }{d}

Where D is the distance of the slit to the screen

   Hence

        D  =  \frac{y *  d}{\lambda }

substituting values

       D  =  \frac{ 4.2 *10^{-3} *   0.29 *10^{-3}}{ 476.1 *10^{-9} }

        D  =  2.6 \ m

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4 years ago
Average weather conditions in a specific location for a long time
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7 0
3 years ago
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AleksandrR [38]

Answer:

304.86 metres

Explanation:

The x and y cordinates are dcos\theta and dsin\theta respectively

The horizontal distance travelled, x=v_{ox}t=dcos\theta

Making t the subject, t=\frac{dcos\theta}{v_{ox}}

Since y=0.5gt^2=dsin\theta, we substitute t with the above and obtain

0.5g(\frac{dcos\theta}{v_{ox}})^2=dsin\theta

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d=\frac{2v_{ox}^2sin\theta}{gcos^2\theta}

d=\frac{2*30^2sin48}{9.8cos^248}

d=304.8584

d=304.86m

5 0
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