Answer:
1. B
2. E
3. A
4. D
5. C
~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Hope I helped!!!
GL :)
Answer:
4.2 m
Explanation:
The energy (E) of the selector region of the spectrometer is:
E = v*B (equation 1)
Where v is the velocity, and B the magnetic field.
The force with which particle forms a curved path can be calculated by:
Where r is the radius of the particle, m is the mass, and q the electric charge. So:
For equation 1: v = E/B, so:
The two species will be separated by Δr = 0.42 mm
Δr = Δm*E/(q*B*B')
E/(q*B*B') = r/m
Δr = Δm*r/m
r = m*Δr/Δm
r is the large of curvature, m is the avarege mass = (28.0106 + 28.0134)/2 = 28.012:
r = (28.012*0.42)/(28.0134 - 28.0106)
r = 11.76504/(0.0028)
r = 4201.8 mm
r = 4.2 m
Answer:
0.170 M
Explanation:
As this is a <em>series of dilutions</em>, we can continuosly<em> use the C₁V₁=C₂V₂ formula </em>to solve this problem:
For the first step:
- 59.0 mL * 1.80 M = 258 mL * C₂
Then for when 129 mL of that 0.412 M are diluted by adding 183 mL of water:
- V₂ = 129 mL + 183 mL = 312 mL
Using <em>C₁V₁=C₂V₂:</em>
- 129 mL * 0.412 M = 312 mL * C₂
Answer:
Multiply the number of moles of butane by its molar mass, 58.12g/mol, to produce the mass of butane. Mass of butane = 18.8g.
Explanation:
Part B:
The mass of water produced when 4.86 g of butane(C4H10) react with excess oxygen is calculated as below
calculate the moles of C4H10 used = mass/molar mass
moles = 4.86g/58 g/mol =0.0838 moles
write a balanced equation for reaction
2 C4H10 + 13 O2 = 8 CO2 + 10 H2O
by use of mole ratio between C4H10 to H2O which is 2:10 the moles of
H20= 0.0838 x10/2 = 0.419 moles of H2O
mass = moles x molar mass
=0.419 molx 18 g/mol = 7.542 grams of water is formed
