Question

Use the equation editor or "Insert Chemistry - WIRIS editor" to write the balanced molecular chemical equation for the reaction of aqueous 0.34 M copper (II) nitrate, with 0.70 M potassium carbonate. You may need to consult Appendix E to determine the states of each reactant and product. Assume any insoluble products are completely insoluble.

Answer 1

Answer:

The balanced molecular equation  for the reaction :

$Cu(NO_3)_2(aq)+K_2CO_3(aq)\rightarrow CuCO_3(s)+2KNO_3(aq)$

Explanation:

The reaction between copper(II) nitrate  and potassium carbonate gives solid precipitate of copper(II) carbonate and aqueous solution of potassium nitrate.

$Cu(NO_3)_2(aq)+K_2CO_3(aq)\rightarrow CuCO_3(s)+2KNO_3(aq)$

According to reaction, 1 mole of copper(II) nitrate reacts with 1 mole of potassium carbonate to give 1 mole of copper(II) carbonate and 2 moles of potassium nitrate,