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Leya [2.2K]
3 years ago
7

Use the equation editor or "Insert Chemistry - WIRIS editor" to write the balanced molecular chemical equation for the reaction

of aqueous 0.34 M copper (II) nitrate, with 0.70 M potassium carbonate. You may need to consult Appendix E to determine the states of each reactant and product. Assume any insoluble products are completely insoluble.
Chemistry
1 answer:
Mariana [72]3 years ago
8 0

Answer:

The balanced molecular equation  for the reaction :

Cu(NO_3)_2(aq)+K_2CO_3(aq)\rightarrow CuCO_3(s)+2KNO_3(aq)

Explanation:

The reaction between copper(II) nitrate  and potassium carbonate gives solid precipitate of copper(II) carbonate and aqueous solution of potassium nitrate.

Cu(NO_3)_2(aq)+K_2CO_3(aq)\rightarrow CuCO_3(s)+2KNO_3(aq)

According to reaction, 1 mole of copper(II) nitrate reacts with 1 mole of potassium carbonate to give 1 mole of copper(II) carbonate and 2 moles of potassium nitrate,

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A buffer solution contains an equivalent amount of acid and base. The pH of the solution with an acid dissociation constant (pKa) value of 3.75 is 3.82.

<h3>What is pH?</h3>

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Given,

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