1 mole of nacl has 1 mole of na ions
therefore 2 moles of nacl has 2 moles of na ions
Mole x L
= 2x6.02x10^23
=12.04 x 10^23
2.258302785 x
atoms of titanium are present in a sample containing 0.375 moles of Ti.
<h3>What are moles?</h3>
A mole is defined as 6.02214076 × 10^{23} of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.
To find the number atoms we need to multiply by 6.02214076 × 10^{23}.
0.375 moles x 6.02214076 × 
2.258302785 x 
Hence, 2.258302785 x
atoms of titanium are present in a sample containing 0.375 moles of Ti.
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Answer:
(a) HCl
(b) HCl
(c) HCl
(d) HCl
Explanation:
<em>Given: </em>0.50 mol of CH₄ and 1.0 mol of HCl
Using stoichiometry we can calculate the answers to parts a, b, c, and d.
<h3>Part (a) </h3>
# of moles × Avogadro's number = # of atoms or molecules
Avogadro's number: 6.02 * 10²³
HCl has more atoms than CH₄.
<h3>Part (b) </h3>
This is calculated the same way as Part (a); HCl has more molecules than CH₄.
<h3>Part (c) </h3>
Molar mass of CH₄ = 16.04 g/mol
Molar mass of HCl = 36.458 g/mol
HCl has a greater mass than CH₄.
<h3>Part (d)</h3>
Assuming STP:
Molar volume of any gas at STP is 22.4 L/mol.
HCl has a greater volume than CH₄.
Substances that will make a salt when combined is Soda and Ammonia
The concentration of hydrogen ions in a solution is a measure of its acidity. So the correct option is (b) false.
When an Arrhenius acid is dissolved in water, hydrogen ions are produced:
H+(aq) + A- = HA + H2O (aq)
Here, H+ is the hydrogen cation, A- is the solvated anion, also known as the conjugate base, and HA is the non-dissociated acid. When an Arrhenius base is dissolved in water, hydroxide ions are produced:
BOH + H2O → B+(aq) + OH-(aq)
Is a material with at least one hydrogen atom that has the ability to split apart in an aqueous solution to produce an anion and an H + ion (a proton), creating an acidic solution. Bases are substances that, when dissolved in water, create hydroxide ions (OH) and a cation, resulting in a basic solution.
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