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g100num [7]
3 years ago
10

Consider a physical situation in which a particle moves from point A to point B. This process is described from two coordinate s

ystems that are identical except that they have different origins.
The __________ of the particle at point A differ(s) as expressed in one coordinate system compared to the other, but the __________ from A to B is/are the same as expressed in both coordinate systems.
Physics
2 answers:
Fudgin [204]3 years ago
8 0

Coordinates, displacement

solong [7]3 years ago
3 0

Coordinates, displacement  are the answers

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Find the magnitude of u × v and the unit vector parrallel to u × v in the direction of u × v. u = 2i + 2j - k, v = -i + k
IrinaVladis [17]

Answer:

magnitude = 3

unit vector = \frac{2i}{3} - \frac{j}{3} - \frac{2k}{3}

Explanation:

Given vectors:

u = 2i + 2j - k

v = -i + k = -i + 0j + k

(a) u x v is the cross product of u and v, and is given by;

u X v = \left[\begin{array}{ccc}i&j&k\\2&2&-1\\-1&0&1\end{array}\right]

u x v = i(2+0) - j(2 - 1) + k(0 - 2)

u x v = 2i - j - 2k

Now the magnitude of u x v is calculated as follows:

| u x v | = \sqrt{2^2 + (-1)^2 + (-2)^2}

| u x v | = \sqrt{4 + 1 + 4}

| u x v | = \sqrt{9}

| u x v | = 3

Therefore, the magnitude of u x v is 3

(b) The unit vector û parallel to u x v in the direction of u x v is given by the ratio of u x v and the magnitude of u x v. i.e

û = \frac{u X v}{|u X v|}        

u x v = 2i - j - 2k        [<em>calculated in (a) above</em>]

|u x v| = 3                   [<em>calculated in (a) above</em>]

∴ û = \frac{2i - j - 2k}{3}

∴ û = \frac{2i}{3} - \frac{j}{3} - \frac{2k}{3}

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3 years ago
Calculate the force of gravity on the 1.2-kg mass if it were 1.9×107 m above earth's surface (that is, if it were four earth rad
Anettt [7]

Answer:

Force of gravity, F = 0.74 N

Mass of an object, m = 1.2 kg

Distance above earth's surface, d=1.9\times 10^7\ m

Mass of Earth, M=5.97\times 10^{24}\ kg

Radius of Earth, r=6.37\times 10^6\ m

We need to find the force of gravity above the surface of Earth. It is given by :

F=G\dfrac{mM}{R^2}

R = r + d

R = 25370000 m

F=6.67\times 10^{-11}\times \dfrac{5.97\times 10^{24}\ kg\times 1.2\ kg}{(25370000\ m)^2}

F = 0.74 N

So, the force of gravity on the object is 0.74 N. Hence, this is the required solution.

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If a 3.1 kg ring of granite decreases in temperature 17.9C. What is the
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