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3 years ago

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Consider a physical situation in which a particle moves from point A to point B. This process is described from two coordinate s

ystems that are identical except that they have different origins.
The __________ of the particle at point A differ(s) as expressed in one coordinate system compared to the other, but the __________ from A to B is/are the same as expressed in both coordinate systems.

2 answers:

Fudgin [204]3 years ago

8 0

Coordinates, displacement

solong [7]3 years ago

3 0

Coordinates, displacement are the answers

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A pulsar is a rapidly rotating neutron star that emits a radio beam the way a lighthouse emits a light beam. We receive a radio

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Answer:

a). $a_p=-2.39x10^{-12} rad/s^2$

b). $t=1016298.8 years$

c). $T_i=80.58x10^{-3}s$

Explanation:

a).

The acceleration for definition is the derive of the velocity so:

$a_p=\frac{dw}{dt}$

$w=\frac{2\pi}{t}$

$a_p=\frac{dw}{dt}=-\frac{2\pi}{t^2}*\frac{dT}{dt}$

$dT=0.0808s$

$dt=1 year*\frac{365d}{1year} \frac{24hr}{1d} \frac{60minute}{1hr} \frac{60s}{1minute}=31.536x10^{6}s$

Replacing

$a_p=-\frac{2\pi}{0.082s^2}*\frac{9.84x10^{-7}}{31.536x10^{6}s}= -2.39x10^{-12} rad/s^2$

b).

If the pulsar will continue to decelerate at this rate, it will stop rotating at time:

$t=\frac{w}{a_p}$

$w=\frac{2\pi }{t}=\frac{2\pi }{0.0820s}=76.62 rad/s$

$t=\frac{76.62 rad/s}{2.39x10^{-12}rad/s^2}= 3.2058x10^{13}s$

$t=1016298.8 years$

c).

582 years ago to 2019

1437

$T_i=0.0820-9.84x10^{-7}*1437)=80.58x10^{-3}s$

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4 years ago

Which statement describes the relationship between the rate of reaction and the temperature?

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PM me the statements, and i'll answer it then.

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3 years ago

7. A scientist studying a squid observes that the squid at rest

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The average force on the squid during the ejection of 0.60 kg of water at a velocity of 15.0 m/s in 0.15 seconds is 60 N.

We can calculate the average force with the average acceleration as follows:

$F = m\overline{a}$ (1)

Where:

m: is the mass of water = 0.60 kg

$\overline{a}$ : is the average acceleration

The <em>average acceleration</em> is given by the change of velocity in an interval of time

$\overline{a} = \frac{v_{f} - v_{i}}{t_{f} - t_{i}}$ (2)

Where:

$v_{i}$ : is the initial velocity = 0 (the squid is at rest)

$v_{f}$ : is the final velocity = 15.0 m/s

$t_{i}$ : is the initial time = 0

$t_{f}$ : is the final time = 0.15 s

Now we can find the <em>average force</em> after entering equation (2) into (1)

$F = m(\frac{v_{f} - v_{i}}{t_{f} - t_{i}}) = 0.60 kg(\frac{15.0 m/s - 0}{0.15 s}) = 60 N$

Therefore, the average force on the squid during the propulsion is 60 N.

Find more about average force here:

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3 years ago

A 80 kg block starts from rest at the top of a 15m frictionless ramp. The block slides down the frictionless ramp onto a rough h

Nadusha1986 [10]

Answer:

W(fric) = -12000 J

Explanation:

Given that

mass ,m= 80 kg

Initial speed ,u= 0 m/s

Height ,h= 15 m

Final speed ,v= 0 m/s

We know that

Work done by all the forces = Change in the kinetic energy

$W_{gravity}+W_{fric}=\dfrac{1}{2}mv^2-\dfrac{1}{2}mu^2$

$W_{gravity}+W_{fric}=\dfrac{1}{2}m\times 0^2-\dfrac{1}{2}m\times 0^2$

$W_{gravity}+W_{fric}=0$

W(fric)= - m g h

W(fric) = - 80 x 10 x 15 ( g=10 m/s²)

W(fric) = -12000 J

negative sign indicates that force and displacement is in opposite direction.

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4vir4ik [10]

Answer:

evaporating water from its skin

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