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Molodets [167]
3 years ago
12

Which of these gets so bright as to be seen in daylight at times? mars saturn jupiter mercury venus?

Physics
2 answers:
fenix001 [56]3 years ago
8 0
While these could all be seen with a telescope during daytime, Venus<span> is the only one that could be viewed with the naked eye in daylight.</span>
tamaranim1 [39]3 years ago
5 0
Venus sometimes does that.
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a 70 kg desk sits on the floor motionless If gravity is pulling it with an acceleration of 9.8 m/s/s how much force is gravity e
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Since force is mass*acceleration,

F = 70kg * 9.8 m/s

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4 years ago
Identify the variables from the experiment below.
AURORKA [14]

Hight of plants - dependent variable.

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6 0
4 years ago
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Building codes usually limit the current carried by a No. 14 copper wire to 15 A. Many household circuits are wired with this si
Sedbober [7]

Answer:

The drift velocity of the electrons in this case is c) 5.52 x 10-4 m/s

Explanation:

Hi

First of all, we need to find the volume occupied by 63.3g of copper, so V=\frac{m}{\rho}= \frac{0.0633Kg}{8,900kg/m^{3}} =7.11 \times 10^{-6} m^{3}, then if we assume each atom of copper contributes with one free electron to the material body n=\frac{N_{A}}{V}=\frac{6.02 \times 10^{23} electrons}{7.11 \times 10^{-6} m^{3}} =8.46 \times 10^{28} electrons/m^{3}.

Finally, we apply v_{d}=\frac{I}{nqA}, where A is area so, A=\pi (\frac{d}{2})^{2}= \pi (\frac{0.0016m}{2})^{2}=2 \times 10^{-6} m^{2}, thus v_{d}=\frac{I}{nqA}=\frac{15C/s}{(8.46 \times 10^{28} m^{-3})(1.60 \times 10^{-19} C)(2 \times 10^{-6} m^{2})}=5.50 \times 10^{-4} m/s.

As we can see c. 5.52 x 10-4 m/s is the nearest one.

3 0
3 years ago
"Your are flying in Class C airspace and the controller says, "radar service is terminated". What should the transponder be set
EleoNora [17]

Answer:

Who knows

Explanation:

8 0
4 years ago
You leave your home at 1pm. At 3pm, you are 100 km east of your house. What was your average velocity in km/hr
Rasek [7]

Answer:

50km/h

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Average velocity = change in distance (or distance travelled) divided by/ the change in time (or time taken.)

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Therefore the average velocity was 100/2 = 50km/h (to the east).

Hope this helped!

4 0
3 years ago
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