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Papessa [141]
2 years ago
5

Indicate the compartment (A or B) that will increase in volume for each of the following pairs of solutions separated by a semi-

permeable membrane: A B a. 20% (m/v) starch b. 10% (m/v) albumin c. 0.5% (m/v) sucrose 10% (m/v) starch 2% (m/v) albumin 5% (m/v) sucrose​
Chemistry
1 answer:
avanturin [10]2 years ago
4 0

Based on the concentration of the solutions, the increase in volume is as follows:

  • the volume of the 20% (m/v) starch increases
  • the volume of the 10% (m/v) albumin increases
  • the volume of the 5% (m/v) sucrose increases

<h3>What is osmosis?</h3>

Osmosis is the movement of water molecules from a region of low solute concentration to a region of high solute concentration through a semipermeable membrane.

The movement of water molecules in the solution pairs is as follows:

  • the volume of the 20% (m/v) starch increases because water moves in from the 10% (m/v) starch solution.
  • the volume of the 10% (m/v) albumin increases because water moves in from the 2% (m/v) albumin
  • the volume of the 5% (m/v) sucrose increases because water moves in from the 0.5% (m/v) sucrose.

Therefore, the increase in volume depends on the concentration ofvthe solutions.

Learn more about osmosis at: brainly.com/question/2625460

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Given 4.80g of ammonium carbonate, find:
V125BC [204]

Answer:

1) 0.05 mol.

2) 0.1 mol.

3) 0.05 mol.

4) 0.4 mol.

5) 2.4 x 10²³ molecules.

Explanation:

<em>1) Number of moles of the compound:</em>

no. of moles of ammonium carbonate = mass/molar mass = (4.80 g)/(96.09 g/mol) = 0.05 mol.

<em>2) Number of moles of ammonium ions :</em>

  • Ammonium carbonate is dissociated according to the balanced equation:

<em>(NH₄)₂CO₃ → 2NH₄⁺ + CO₃²⁻.</em>

It is clear that every 1.0 mole of (NH₄)₂CO₃ is dissociated to produce 2.0 moles of NH₄⁺ ions and 1.0 mole of CO₃²⁻ ions.

<em>∴ The no. of moles of NH₄⁺ ions in 0.05 mol of (NH₄)₂CO₃ </em>= (2.0)(0.05 mol) =  <em>0.1 mol.</em>

<em>3) Number of moles of carbonate ions :</em>

  • Ammonium carbonate is dissociated according to the balanced equation:

<em>(NH₄)₂CO₃ → 2NH₄⁺ + CO₃²⁻.</em>

It is clear that every 1.0 mole of (NH₄)₂CO₃ is dissociated to produce 2.0 moles of NH₄⁺ ions and 1.0 mole of CO₃²⁻ ions.

∴ The no. of moles of CO₃²⁻ ions in 0.05 mol of (NH₄)₂CO₃ = (1.0)(0.05 mol) = 0.05 mol.

<em>4) Number of moles of hydrogen atoms:</em>

  • Every 1.0 mol of (NH₄)₂CO₃  contains:

2.0 moles of N atoms, 8.0 moles of H atoms, 1.0 mole of C atoms, and 3.0 moles of O atoms.

<em>∴ The no. of moles of H atoms in 0.05 mol of (NH₄)₂CO</em>₃ = (8.0)(0.05 mol) = <em>0.4 mol.</em>

<em>5) Number of hydrogen atoms:</em>

  • It is known that every mole of a molecule or element contains Avogadro's number (6.022 x 10²³) of molecules or atoms.

<u><em>Using cross multiplication:</em></u>

1.0 mole of H atoms contains → 6.022 x 10²³ atoms.

0.4 mole of H atoms contains → ??? atoms.

<em>∴ The no. of atoms in  0.4 mol of H atoms</em> = (6.022 x 10²³ molecules)(0.4 mole)/(1.0 mole) = <em>2.4 x 10²³ molecules.</em>

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Compute 6.28×1013+7.30×1011.
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6.28×1013+7.30×1011 this =13741.94
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eimsori [14]

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D. Ap3x just did it

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