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Papessa [141]
2 years ago
5

Indicate the compartment (A or B) that will increase in volume for each of the following pairs of solutions separated by a semi-

permeable membrane: A B a. 20% (m/v) starch b. 10% (m/v) albumin c. 0.5% (m/v) sucrose 10% (m/v) starch 2% (m/v) albumin 5% (m/v) sucrose​
Chemistry
1 answer:
avanturin [10]2 years ago
4 0

Based on the concentration of the solutions, the increase in volume is as follows:

  • the volume of the 20% (m/v) starch increases
  • the volume of the 10% (m/v) albumin increases
  • the volume of the 5% (m/v) sucrose increases

<h3>What is osmosis?</h3>

Osmosis is the movement of water molecules from a region of low solute concentration to a region of high solute concentration through a semipermeable membrane.

The movement of water molecules in the solution pairs is as follows:

  • the volume of the 20% (m/v) starch increases because water moves in from the 10% (m/v) starch solution.
  • the volume of the 10% (m/v) albumin increases because water moves in from the 2% (m/v) albumin
  • the volume of the 5% (m/v) sucrose increases because water moves in from the 0.5% (m/v) sucrose.

Therefore, the increase in volume depends on the concentration ofvthe solutions.

Learn more about osmosis at: brainly.com/question/2625460

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Calculate the [oh] for 0.46 Hcl
Bad White [126]

Answer:

2.17 e -14

Explanation:

A strong acid like HCl ionize 100 % in water so [H3O+] = 0.46 M

[OH-] = Kw /  [H3O+]

        =  1.0 e -14 / 0.46

         = 2.17 e -14

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3 years ago
What going on in each spot
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Water is formed when two hydrogens bond to a oxygen atom
tangare [24]

Answer:

c) a compound

Explanation:

a compound is something made up of two or more separate elements, the separate elements in water are hydrogen(H) and oxygen(O)

6 0
3 years ago
c3H8 + 5O2 = 3CO2 + 4H2O When 44.0 grams of propane (C3H8) under goes complete combustion, how many grams of water will be produ
Umnica [9.8K]

<u>Answer:</u> 72 grams of water will be produced.

<u>Explanation:</u>

To calculate the number of moles, we use the formula:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}    ....(1)

Mass of propane = 44 grams

Molar mass of propane = 44 grams

Putting values in above equation, we get:

\text{moles of propane}=\frac{44g}{44g/mol}=1mole

For the reaction of combustion reaction of propane, the equation follows:

C_3H_8+5O_2\rightarrow 3CO_2+4H_2O

By Stoichiometry of the reaction,

1 mole of propane produces 4 moles of water.

So, 1 mole of propane will produce = \frac{1}{1}\times 4=4moles of water.

Now, to calculate the amount of water, we use equation 1, we get:

Molar mass of water = 18 g/mol

4mol=\frac{\text{Mass of water}}{18g/mol}

Mass of water produced = 72 grams

Hence,  72 grams of water will be produced.

6 0
3 years ago
How many liters of CO2 gas can be produced at 30.0 °C and 1.50 atm from the reaction of 5.00 mol of C3H8 and an excess of O2 acc
lbvjy [14]

Answer:

249 L

Explanation:

Step 1: Write the balanced equation

C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(g)

Step 2: Calculate the moles of CO₂ produced from 5.00 moles of C₃H₈

The molar ratio of C₃H₈ to CO₂ is 1:3. The moles of CO₂ produced are 3/1 × 5.00 mol = 15.0 mol

Step 3: Convert "30.0°C" to Kelvin

We will use the following expression.

K = °C + 273.15

K = 30.0°C + 273.15 = 303.2 K

Step 4: Calculate the volume of carbon dioxide

We will use the ideal gas equation.

P × V = n × R × T

V = n × R × T/P

V = 15.0 mol × 0.0821 atm.L/mol.K × 303.2 K/1.50 atm

V = 249 L

5 0
3 years ago
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