The answer would be B.) The independent variable is the length of the race. The dependent variable is the time.
It’s B because an independent variable is something that is constant and does not change throughout the problem. The dependent variable depends on the independent variable. The race is a 5K race. That will not change. What will change is how long it takes Stephanie to run the 5K race. Hope this helps.
9982 is the correct answer
This might be the perpendicular bisector. I'm not 100% sure.
Answer:
Triangular prism is better deal as the volume of triangular prism is greater.
Step-by-step explanation:
Consider the provided information.
The volume of prism is: ![V=Bh](https://tex.z-dn.net/?f=V%3DBh)
Where B is the base area and h is the height of the prism.
It is given that the trapezoidal prism with a base area of 33 square inches and a height of 4 inches.
The volume of the trapezoidal prism is:
![V=33(4)\\V=132](https://tex.z-dn.net/?f=V%3D33%284%29%5C%5CV%3D132)
Hence, the volume of trapezoidal prism is 132 in³.
Now calculate the volume of triangular prism with a base area of 34 square inches and a height of 5 inches.
The volume of the triangular prism is:
![V=34(5)\\V=170](https://tex.z-dn.net/?f=V%3D34%285%29%5C%5CV%3D170)
Hence, the volume of the triangular prism is 170 in³.
Triangular prism is better deal as the volume of triangular prism is greater.
Answer:
![(Lower=0.61, Upper=0.91)](https://tex.z-dn.net/?f=%20%28Lower%3D0.61%2C%20Upper%3D0.91%29%20)
And using the property of symmetry for the confidence interval we can estimate the sample proportion
with this formula:
![\hat p =\frac{Upper-Lower}{2}= \frac{0.91-0.61}{2}= 0.15](https://tex.z-dn.net/?f=%5Chat%20p%20%3D%5Cfrac%7BUpper-Lower%7D%7B2%7D%3D%20%5Cfrac%7B0.91-0.61%7D%7B2%7D%3D%200.15)
The final answer for this case would be:
![\hat p= 0.15](https://tex.z-dn.net/?f=%5Chat%20p%3D%200.15)
So approximately 15% of teenagers have a sibling.
Step-by-step explanation:
For this case we assume that the proportion of interest is
who represent the number of teenagers who have a sibling and in order to estimate this proportion we can conduct a confidence interval.
The confidence interval for the mean is given by the following formula:
And for this case the confidence interval is given by:
![(Lower=0.61, Upper=0.91)](https://tex.z-dn.net/?f=%20%28Lower%3D0.61%2C%20Upper%3D0.91%29%20)
And using the property of symmetry for the confidence interval we can estimate the sample proportion
with this formula:
![\hat p =\frac{Upper-Lower}{2}= \frac{0.91-0.61}{2}= 0.15](https://tex.z-dn.net/?f=%5Chat%20p%20%3D%5Cfrac%7BUpper-Lower%7D%7B2%7D%3D%20%5Cfrac%7B0.91-0.61%7D%7B2%7D%3D%200.15)
The final answer for this case would be:
![\hat p= 0.15](https://tex.z-dn.net/?f=%5Chat%20p%3D%200.15)
So approximately 15% of teenagers have a sibling.