Question

F(x)=6x^2+10x-1

Answer 1

Answer:

Two different real solutions

Step-by-step explanation:

we know that

In a quadratic equation of the form

$ax^{2} +bx+c=0$

The discriminant D is equal to

$D=b^2-4ac$

Equate f(x) to zero

so

$6x^{2} +10x-1=0$  

we have

$a=6\\b=10\\c=-1$

substitute

$D=10^2-4(6)(-1)$

$D=100+24$

$D=124$

The value of D is greater than zero

That means ----> The quadratic equation has two different real solutions