Answer:
d. ovaries, uterus, and Fallopian tubes
Explanation:
The amount of heat will be equal to Lm.
Where L is the latent heat of fusion and m is mass of the ice.
Latent heat of ice = 80cal/g.
So the amount of heat required here will be 35× 80cal
= 2,800 cal.
Given:
u = 10⁵ m/s, the entrance velocity
v = 2.5 x 10⁶ m/s, the exit velocity
s = 1.6 cm = 0.016 m, distance traveled
Let a = the acceleration.
Then
u² + 2as = v²
(10⁵ m/s)² + 2*(a m/s²)*(0.016 m) = (2.5 x 10⁶ m/s)²
0.032a = 6.25 x 10¹² - 10¹⁰ = 6.24 x 10¹²
a = 1.95 x 10¹⁴ m/s²
Answer: 1.95 x 10¹⁴ m/s²
Answer:
P car = 1500×400/12= 50,000kgm/s
P electron= 9.1×3.5×10^(-31+6)
= 31.85×10^-25 kgm/s
