Answer:
Explanation:
given,
mass of wagon = 20 Kg
horizontal acceleration = 0.5 m/s²
force of pull = 120 N
angle with horizontal = 25°
Applying newtons second law
F cos θ - f = m a
f = F cos θ- ma
f = 120 cos 25° - 20 x 0.5
f = 99 N
we know,
f = μ N
μ =
μ =
μ =
μ = 0.68
Answer:
The frequency of the oscillations in terms of fo will be f2=fo/3
E xplanation:
T= 
=1:3
⇒f2=fo\3
Here frequency f is inversely poportional to square root of mass m.
so the value of remainder of frequency f2 and fo is equal to 1:3.
⇒
= 
⇒
= 1:3
⇒f2=
Answer:
Velocidad en m / s = 72,25 m / s
Explanation:
Dado
Distancia a recorrer por el coche de carreras = 87 Km
1 km = 1000 m
Por lo tanto, 87 km = 87000 m
Tiempo necesario para viajar 87 km / 87000 metros = 20 minutos o 20 * 60 = 1200 segundos
Velocidad en m / s = 87000/1200
Velocidad en m / s = 72,25 m / s
Newton’s Law: F = MA
A = F/M (change equation)
12.6 N/ 2.4 kg = 5.25
Answer: acceleration is 5.25 m/s^2
