Answer:
p = 0.16 kgm/s
Explanation:
the initial momentum combined of the two cars and the final momentum of the paired cares are the same, so we just need to find the initial momentum
p = m1v1 + m2v2
p = 0.04*4 + 0.04*0
p = 0.04*4
p = 0.16 kgm/s
Answer:
(a) A = 0.0800 m, λ = 20.9 m, f = 11.9 Hz
(b) 250 m/s
(c) 1250 N
(d) Positive x-direction
(e) 6.00 m/s
(f) 0.0365 m
Explanation:
(a) The standard form of the wave is:
y = A cos ((2πf) t ± (2π/λ) x)
where A is the amplitude, f is the frequency, and λ is the wavelength.
If the x term has a positive coefficient, the wave moves to the left.
If the x term has a negative coefficient, the wave moves to the right.
Therefore:
A = 0.0800 m
2π/λ = 0.300 m⁻¹
λ = 20.9 m
2πf = 75.0 rad/s
f = 11.9 Hz
(b) Velocity is wavelength times frequency.
v = λf
v = (20.9 m) (11.9 Hz)
v = 250 m/s
(c) The tension is:
T = v²ρ
where ρ is the mass per unit length.
T = (250 m/s)² (0.0200 kg/m)
T = 1250 N
(d) The x term has a negative coefficient, so the wave moves to the right (positive x-direction).
(e) The maximum transverse speed is Aω.
(0.0800 m) (75.0 rad/s)
6.00 m/s
(f) Plug in the values and find y.
y = (0.0800 m) cos((75.0 rad/s) (2.00 s) − (0.300 m⁻¹) (1.00 m))
y = 0.0365 m
Formula for Velocity = DISTANCE traveled/TIME to travel distance + direction
For this one, we can use mph(miles per hour) as unit.
v = 1,000 miles / 336 hours (2 weeks = 24 hours x 14 days = 336 hrs)
= 2.98 mph North
or we can use kph (kilometers per hour)
v = 1609.34 km / 336 hours (1 mile = 1.60934 km)
= 4.79 kph North
The answer is pressure and gravity