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Vinil7 [7]
3 years ago
15

A sample of a compound contains 60.0 g C and 5.05 g H. It’s molar mass is 78.12 g/mol. What is the compound’s molecular formula?

Chemistry
1 answer:
Natalka [10]3 years ago
5 0

Answer:

C6H6

Explanation:

C :     60.0 g*1 mol/12 .01g = 5.00 mol

H:      5.05 g * 1 mol/1.01 g= 5.10 mol

C:H = 5.00 mol : 5.10 mol = 1:1

CH is an empirical formula

Molar mass (12.01 +1.01)=13.02 g/mol

78.12g/mol /13.02 g/mol =6

Molecular formula is the empirical that was taken 6 times (CH)6 = C6H6

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8 0
3 years ago
A compound contains sulfur, oxygen, and chlorine. Analysis shows that it contains by mass 26.95% sulfur and 59.61% chlorine. Wha
sladkih [1.3K]

Answer:

SCl₂

Explanation:

In order to know the empirical formula, we have to follow a series of steps.

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7 0
3 years ago
Read 2 more answers
(C6H6) can be biodegraded by microorganism. if 30 mg of benzene is present, what amount of oxygen required for biodegradation, n
quester [9]

Answer:

36.92 mg of oxygen required for bio-degradation.

Explanation:

5C_6H_6+15O_2\rightarrow 12CO_2+15H_2O

Mass of benzene = 30 mg = 0.03 g (1000 mg = 1 g )

Moles benzene =\frac{0.03 g}{78 g/mol}=0.0003846 mol

According to reaction 5 moles of benzene reacts with 15 moles of oxygen gas.

Then 0.0003846 mol of benzene will react with:

\frac{15}{5}\times 0.0003846 mol=0.0011538 mol of oxygen gas

Mass of 0.0011538 moles of oxygen gas:

0.0011538 mol × 32 g/mol = 0.03692 g = 36.92 mg

36.92 mg of oxygen required for bio-degradation.

4 0
3 years ago
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