A chemist fills a reaction vessel with 0.623g mercurous chloride(Hg2Cl2) solid, 0.645M mercury (I) (Hg2^2+)aqueous solution, and
0.905M chloride (Cl-) aqueous solution at a temperature of 25.0°C.
Under these conditions, calculate the reaction free energy ΔG for the following chemical reaction:
Hg2Cl2(s) ⇌ Hg2^2+ (aq) + 2Cl^- (aq)
Under these conditions, calculate the reaction free energy ΔG for the following chemical reaction:
Hg2Cl2(s) ⇌ Hg2^2+ (aq) + 2Cl^- (aq)
1 answer:
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Answer: The entropy change of the surroundings will be -17.7 J/K mol.
Explanation: The enthalpy of vapourization for 1 mole of acetone is 31.3 kJ/mol
Amount of Acetone given = 10.8 g
Number of moles is calculated by using the formula:
Molar mass of acetone = 58 g/mol
Number of moles =
If 1 mole of acetone has 32.3 kJ/mol of enthalpy, then
0.1862 moles will have =
To calculate the entropy change for the system, we use the formula:
Temperature = 56.2°C = (273 + 56.2)K = 329.2K
Putting values in above equation, we get
(Conversion Factor: 1 kJ = 1000J)
At Boiling point, the liquid phase and gaseous phase of acetone are in equilibrium. Hence,
Answer:
b)15.0°C
Explanation:
Specific Heat of Water=4.2 J/g°C
This means, that 1 g of Water will take 4.2 J of energy to increase its temperature by 1°C.
∴80 g Water will take 80×4.2 J of energy to increase its temperature by 1°C.
80×4.2 J=336 J
Total Energy Provided=1680 J
The temperature increase=\frac{\textrm{Total energy required}}{\textrm{energy required to increase temperature by one degree}}
Temperature increase=
=5°C
Initial Temperature =10°C
Final Temperature=Initial + Increase in Temperature
=10+5=15°C