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xeze [42]
2 years ago
13

A car is traveling 70km in 45 minutes. How many miles an hour is the car traveling?

Chemistry
1 answer:
labwork [276]2 years ago
5 0

52

Explanation:

70x45÷60= 52

I hope this is helpful

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Pretend that you are the size of an atom, observing a reaction between a potassium atom and a fluorine atom. Write an account of
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 <span>Each atom in an ionic compound tends either to empty or complete the shell to 8 electrons. So when the number of electrons on the external shell is near 8 , the atom tends to attract electrons to complete the shell giving a positive ion called anion 
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What type of flower is this? This is for a science project.
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. How many moles of ammonia gas, NH3, are required to fill a volume of 50 liters at STP?
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In STP every 22.4 litters is 1 mol
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A 7.12 L cylinder contains 1.21 mol of gas A and 4.94 mol of gas B, at a temperature of 28.1 °C. Calculate the partial pressure
GenaCL600 [577]

Answer:

P_A=4.20atm\\\\P_B=17.1atm

Explanation:

Hello!

In this case, since the equation for the ideal gas is:

PV=nRT

For each gas, given the total volume, temperature (28.1+273.15=301.25K) and moles, we can easily compute the partial pressure as shown below:

P_A=\frac{n_ART}{V} =\frac{1.21mol*0.082\frac{atm*L}{mol*K}*301.25K}{7.12L} \\\\P_A=4.20atm\\\\P_B=\frac{n_BRT}{V} =\frac{4.94mol*0.082\frac{atm*L}{mol*K}*301.25K}{7.12L} \\\\P_B=17.1atm

Best regards!

8 0
3 years ago
A sample of a compound of xenon and fluorine contains molecules of a single type; XeFn, where n is a whole number. If 5.0 x 1020
kicyunya [14]

Answer:

4

Explanation:

Avogadro’s number represent the number of the constituent particles which are present in one mole of the substance. It is named after scientist Amedeo Avogadro and is denoted by N_0.

Also, it is the number of particles in exactly 12.000 g of isotope carbon 12.

Avogadro constant:-

N_a=6.023\times 10^{23}

Hence,

Mass of XeF_n = 131.293+ n18.998 g

So,

6.023\times 10^{23}  molecules have a mass of 131.293+ n18.998 g

Also,

1  molecules have a mass of \frac{(131.293+ n18.998)}{6.023\times 10^{23}} g

So,

5.0\times 10^{20}  molecules have a mass of \frac{(131.293+ n18.998)}{6.023\times 10^{23}}\times 5.0\times 10^{20} g

Also, given mass = 0.172 g

Thus,

\frac{(131.293+ n18.998)}{6.023\times 10^{23}}\times 5.0\times 10^{20}=0.172

\frac{18.998n+131.293}{1204.6}=0.172

18.998n+131.293=207.1912

n=\frac{75.8982}{18.998}=4

<u>Thus, value of n is 4.</u>

4 0
3 years ago
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