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DedPeter [7]
4 years ago
13

Where is the electric field zero? a. region 2, 0.46 m from the +7 µC charge b. region 2, 0.46 m from the +5 µC charge c. the fie

ld is not zero anywhere on the x axis (except at infinity)d. region 3, 0.46 m from the +7 µC chargee. region 1, 0.46 m from the +5 µC charge
Physics
1 answer:
Ratling [72]4 years ago
3 0

Answer:

the field is not zero anywhere on the x axis (except at infinity)

Explanation:

From the Coulomb's law we have electric field intensity as:

E=\frac{1}{4\pi.\epsilon_o} \frac{q}{r^2}

where:

\epsilon_o= permittivity of free space

q= charge due to which the field is generated.

r= distance from the charge

So, from the above relation:

Electric field due to a charge can only be zero at infinity.

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A bus initially moving at 20 m/s with an acceleration of -4m/s² for 5
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Answer:

50m; 0m/s.

Explanation:

Given the following data;

Initial velocity = 20m/s

Acceleration, a = - 4m/s²

Time, t = 5secs

To find the displacement, we would use the second equation of motion;

S = ut + \frac {1}{2}at^{2}

Substituting into the equation, we have;

S =20*5 + \frac{1}{2}*(-4)*5^{2}

S =100 + (-2)*25

S =100 - 50

S = 50m

Next, to find the final velocity, we would use the third equation of motion;

V^{2} = U^{2} + 2aS

Where;

  • V represents the final velocity measured in meter per seconds.
  • U represents the initial velocity measured in meter per seconds.
  • a represents acceleration measured in meters per seconds square.

<em>Substituting into the equation, we have;</em>

V^{2} = 20^{2} + 2(-4)*50

V^{2} = 400 - 400

V^{2} = 0

V = 0m/s

<em>Therefore, the displacement of the bus is 50m and its final velocity is 0m/s.</em>

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