Answer:
C. The facial feedback theory
Explanation:
The facial feedback theory as postulated by William James and connects back to the famous Charles Darwin talks about how facial expressions stimulate our emotional state of being. Based on this theory, the emotional experiences we have are determined by the looks on our faces.
According to the question, smiling at an event makes you enjoy it is an example of what the The facial feedback theory is explaining. Furthermore, smiling, which is a facial expression causes or stimulates an emotional state of enjoyment in that event.
Answer:
Explanation:
All substances have characteristic physical and chemical properties. Physical properties are those that can be observed with the senses without changing the identity of the substance. Chemical properties describe how a substance can be changed into a new substance. Physical and chemical properties, such as color, density, boiling point, solubility, conductivity, and flammability, A. are always different between substances. B. depend on the amount of the substance. C. do not depend on the amount of the substance. D. have the same values for all substances.
Ask for details Follow Report by S27754738 2 hours ago
Answers
To be able to determine the original speed of the car, we use kinematic equations to relate the acceleration, distance and the original speed of the car moving.
First, we manipulate the one of the kinematic equations
v^2 = v0^2 + 2 (a) (x) where v = 0 since the car stopped
Writing the equation in such a way that the initial velocity or v0 is written on one side of the equation,
<span>we get v0 = sqrt (2(a)(x))
Substituting the known values,
v0 = sqrt(2(3.50)(30.0))
v0 = 14.49 m/s
</span>
Therefore, before stopping the car the original speed of the car would be 14.49 m/s
Answer:
The fraction of the protons would have no electrons ![=1.88\times 10^{-10}](https://tex.z-dn.net/?f=%3D1.88%5Ctimes%2010%5E%7B-10%7D)
Explanation:
We are given that
Amoeba has total number of protons=![1.00\times 10^{16}](https://tex.z-dn.net/?f=1.00%5Ctimes%2010%5E%7B16%7D)
Net charge, Q=0.300pC
Electrons are fewer than protons=![1.88\times 10^6](https://tex.z-dn.net/?f=1.88%5Ctimes%2010%5E6)
We have to find the fraction of protons would have no electrons.
The fraction of the protons would have no electrons
=![\frac{Fewer\;electrons}{Total\;protons}](https://tex.z-dn.net/?f=%5Cfrac%7BFewer%5C%3Belectrons%7D%7BTotal%5C%3Bprotons%7D)
The fraction of the protons would have no electrons
=![\frac{1.88\times 10^{6}}{1.00\times 10^{16}}](https://tex.z-dn.net/?f=%5Cfrac%7B1.88%5Ctimes%2010%5E%7B6%7D%7D%7B1.00%5Ctimes%2010%5E%7B16%7D%7D)
![=1.88\times 10^{-10}](https://tex.z-dn.net/?f=%3D1.88%5Ctimes%2010%5E%7B-10%7D)
Hence, the fraction of the protons would have no electrons ![=1.88\times 10^{-10}](https://tex.z-dn.net/?f=%3D1.88%5Ctimes%2010%5E%7B-10%7D)