Two families meet at the park at 10:00am. Each family uses a different way of transportation to get there. The Gonzalez family l
eaves at 9:00am and drives 90 km on a highway. The Rivera leave at 9:30am and ride the train 30km. What is the average speed for each family’s trip? Which family travels at the faster speed?
Firstly, we need to make the times and distance equal to compare.
1hr=60mins Gonz drove 90km in 60mins,so they would drive 45km in 30 mins dividing it by 2. Because the Rivs had gone 30km in 30mins, Gonz were faster.
For the adverage speed, we should first add the speed of each family in mph , so 90+60, which equals 150 and divide that by 2 because there are 2 speeds so the average speed is 75mph.
P.S English is my second language so tell me if you don't understand something and I will try and explain.
By the law of reflection which says that the angle of reflection is equal to the angle of incidence, which in other words says, sin x = sin y, it can be said, based on the given that the angle of reflection is also equal to the angle of incidence of 35 degrees
Power required to climb= Fv where F is force and v is soeed. We know that F= mg hence Power, P= mgv and substituting 700 kg for m, 9.81 for g and 2.5 m/s for v then
P= 700*9.81*2.5=17167.5 W= 17.1675 kW
To express it as a fraction of 75 kw then 17.1675/75=0.2289 or 22.89%
