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navik [9.2K]
3 years ago
10

Two families meet at the park at 10:00am. Each family uses a different way of transportation to get there. The Gonzalez family l

eaves at 9:00am and drives 90 km on a highway. The Rivera leave at 9:30am and ride the train 30km. What is the average speed for each family’s trip? Which family travels at the faster speed?
Physics
1 answer:
pav-90 [236]3 years ago
5 0

Firstly, we need to make the times and distance equal to compare.

1hr=60mins
Gonz drove 90km in 60mins,so they would drive 45km in 30 mins dividing it by 2.
Because the Rivs had gone 30km in 30mins, Gonz were faster.

For the adverage speed, we should first add the speed of each family in mph , so 90+60, which equals 150 and divide that by 2 because there are 2 speeds so the average speed is 75mph.

P.S English is my second language so tell me if you don't understand something and I will try and explain.
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Explanation:

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λ = (6.626 x 10⁻³⁴ J.s)(3 x 10⁸ m/s)/(7.2 x 10⁻¹⁹ J)

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Answer:

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  •  coefficient of restitution =\frac{v}{u}

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        therefore the outgoing kinetic energy = 0.5 x m x (0.72u)^{2}

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        outgoing kinetic energy = 0.5184 (0.5 x m x x u^{2})

recall that 0.5 x m x x u^{2} is our incoming kinetic energy, therefore

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