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german
3 years ago
14

A charming friend of yours who has been reading a little bit about astronomy accompanies you to the campus observatory and asks

to see the kind of star that our Sun will ultimately become, long, long after it has turned into a white dwarf. Why is the astronomer on duty going to have a bit of a problem satisfying her request? a. All the old stars in our Galaxy are located in globular clusters and all of these are too far away to be seen with the kind of telescope a college or university campus would have. b. After being a white dwarf, the Sun will explode, and there will be nothing left to see. c. The universe is not even old enough to have produced any white dwarfs yet d. Astronomers only let people with PhD's look at these stellar corpses; it's like an initiation rite for those who become astronomers. e. After a white dwarf cools off it becomes too cold and dark to emit visible light
Physics
1 answer:
lidiya [134]3 years ago
3 0

Answer:

b

Explanation:

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Both gamma rays and x-rays are used to see inside the body. True or False
lozanna [386]

Answer:

True

Explanation:

Gamma rays and X-rays are made of packets of energy (photons) without mass or charge, with high penetrating power such that they can pass through the human body and impinge on a photographic plate creating an image of the interior of the human body. They electromagnetic radiation of high energy and high frequency that emanate from some natural sources such as cosmic sun rays and radon gas.

Gamma rays and X-rays can be man made by use of man made electronic devices and radioactive elements

Gamma rays and X-rays find use in airport security scanning and imaging services for medical testing.

8 0
3 years ago
In some applications of ultrasound, such as its use on cranial tissues, large reflections from the surrounding bones can produce
worty [1.4K]

Answer:

b. 0.75 mm

Explanation:

The distance between antinodes d is half the wavelength \lambda. We can obtain the wavelength with the formula v=\lambda f, where f is the frequency given (f=1MHz=1\times10^6Hz) and v is the speed of sound in body tissues (v=1540m/s), so putting all together we have:

d=\frac{\lambda}{2}=\frac{v}{2f}=\frac{1540m/s}{2(1\times10^6Hz)}=0.00077m=0.77mm

which is very close to the 0.75mm option.

4 0
4 years ago
A solvent passes through a chromatography column in 3.0 minutes, but the solute requires 9.0 minutes.
Sergio [31]

Answer:

(a). 2

(b). 1/3

(c). 11.11

Explanation:

(a).  k= (t₍s₎-t₍o₎)/t₍o₎...............(1)

where k= retention factor,

t₍o₎=solvent time, t₍s₎= solute time.

Given t₍s₎=9.0 Minutes, t₍o₎=3.0 minutes.

∴ k= (9-3)/3

  k= 2.

(b). the fraction of time the solute spend in the mobile phase in the column is the ratio of the solvent time to the solute time. = t₍o₎/t₍s₎..........(2)

= 3/9

=1/3.

(c). K=k(Vm/Vs)................(3)

where K= partition coefficient, k= retention factor, Vm=volume of mobile phase, Vs= volume of stationary phase.

∴K = k(Vm/Vs)

k=2, and Vs=0.18Vm.

∴K = 2(Vm/0.18vm)

⇒K = 2/0.18

∴K=11.11

4 0
3 years ago
A galvanometer with a resistance of 40.0 ω deflects full scale at a current of 2.0 ma. what resistance should be used with this
kogti [31]
The resistance needed to be added is R
The Current is 2 ma
The voltage reading is a maximum of 50 volts.
The ma meter has an internal resistance of 40 ohms.

Formula
E = I * R

Givens
E = 50
I = 2 ms
R = R + 40

Solution
E = I * R
I = 2 ma [ 1 amp / 1000 ma] = 0.002 amp
50 = 0.002 * (R + 40)  Divide by 0.002
50/0.002 = R + 40
25000 = R + 40 Subtract 40 from both sides.
R = 25000 - 40
R = 24960     Answer

8 0
3 years ago
Read 2 more answers
If Mercury, moved two orbital paths closer to the sun: what would be different? List serval differences, ideas.......
elena-14-01-66 [18.8K]
Well first of all, when it comes to orbits of the planets around
the sun, there's no such thing as "orbital paths", in the sense
of definite ("quantized") distances that the planets can occupy
but not in between.  That's the case with the electrons in an atom,
but a planet's orbit can be any old distance from the sun at all. 

If Mercury, or any planet, were somehow moved to an orbit closer
to the sun, then ...

-- its speed in orbit would be greater,

-- the distance around its orbit would be shorter,

-- its orbital period ("year") would be shorter,

-- the temperature everywhere on its surface would be higher,

-- if it has an atmosphere now, then its atmosphere would become
less dense, and might soon disappear entirely,

-- the intensity of x-rays, charged particles, and other forms of
solar radiation arriving at its surface would be greater.
5 0
3 years ago
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