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2 years ago

How can larger telescopes

Physics

1 answer:

alexira [117]2 years ago

8 0

Answer:

Explanation:

"Larger telescopes" generally means larger apertures. This is the part of the telescope which collects the light. The more light collected, the more clear the picture becomes

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The load across a 12 v battery consists of a series combination of three resistors 45 ω, 55 ω, and 35 ω. what is the total resis

zubka84 [21]

For n resistors in series, the equivalent resistance is given by the sum of the resistances:
$R_{eq} = R_1 + R_2 + ... + R_n$

In this problem, we have three resistors, so the equivalent resistance of the load is the sum of the resistances of the three resistors:
$R_{eq}=45 \Omega + 55 \Omega + 35 \Omega =135 \Omega$

5 0

3 years ago

A bridge to be fabricated of steel girders is designed to be 500 m long and 12 m wide at ambient temperature (assumed 20°C). Exp

andrew-mc [135]

Answer:

21.7391304348 m

Explanation:

L = Initial length = 500 m

$\Delta T$ = Change in temperature = 40-(-35)

$\alpha$ = Coefficient of thermal expansion = $12\times 10^{-6}\ /^{\circ}C$

Change in length is given by

$\Delta L=L\alpha \Delta T\\\Rightarrow \Delta L=500\times 12\times 10^{-6}\times (40-(-35))\\\Rightarrow \Delta L=0.45\ m$

The change in length is 0.45 m

The number of joints would be

$n=\dfrac{0.45}{0.02}\\\Rightarrow n=22.5\\\Rightarrow n\approx 23$

The number of joints is 23

Each bridge section length would be

$\dfrac{L}{n}=\dfrac{500}{23}=21.7391304348\ m$

The length of each bridge section would be 21.7391304348 m

4 0

2 years ago

Two parallel plate capacitors 1 and 2 are identical except that capacitor 1 has charge +q on one plate and charge −q on the othe

Grace [21]

Answer:

a) the capacitance is the same for both capacitors.

b) The potential difference between the plates for the capacitor with charge +2q, is double of the one for the capacitor with charge +q.

c) The electric field magnitude between the plates for the capacitor with charge +2q, is double of the one for the capacitor with charge +q

d) The energy stored between the plates for the capacitor with charge +2q, is 4 times the value for the one with charge +q

Explanation:

a) The capacitance of a capacitor, by definition, is as follows:

$C = \frac{q}{V}$

Appying Gauss' Law to one of plates, it can be showed, that the capacitance (for a parallel plates capacitor) can be expressed as follows:

C = ε*A / d

As it can be seen, it does not depend on the charge. so we conclude that the capacitance must be the same for both capacitors, due to they are identical except for the value of the charge on the plates.

b) By definition, as we said above, the capacitance is equal to the proportion between the charge of one of the plates, and the potential difference between them.

If this proportion must remain the same, and one of the capacitors has the double of the charge than the other, the potential difference must be the double also.

c) Applying Gauss' law, to the surface of one of the plates, and assuming a constant surface charge density σ, it can be showed that the electric field can be calculated as follows:

E*A = Q/ε₀ as σ=Q/A

⇒ E = σ/ε₀

As σ is directly proportional to the charge (being the area A the same), we conclude that the electric field for the capacitor with charge +2q must be the double than the one for the capacitior with charge +q.

c) The electric potential energy, stored between plates of a capacitor, can be written as follows:

$Ue = \frac{1}{2} *\frac{q^{2}}{C}$

If the capacitance remains the same, we can conclude that the electric potential energy for the capacitor with charge +2q, as the charge is raised to the 2nd power, must be 4 times the one for the capacitor with charge +q.

4 0

3 years ago

An example of convection and conduction within a BBQ. I also accept diagrams but please write honestly or I will report.

qwelly [4]

Conduction could be the way in which heat is transferred through a sausage to get it up to cooked temperature. convection could be the air around the barbecue and the smell of the barbecue being carried on thermal convection currents. hope this is honest enough

7 0

2 years ago

A size-5 soccer ball of diameter 22.6 cm and mass 426 g rolls up a hill without slipping, reaching a maximum height of 5.00 m ab

maria [59]

Answer:

W = 0.678 rad/s

Explanation:

Using the conservation of energy:

$E_i =E_f$

Roll up and hill without slipping is the sumatory of two energys, rotational and translational, so:

$\frac{1}{2}IW^2+ \frac{1}{2}mV^2 = mgh$

where I is the moment of inertia, W the angular velocity at the base of the hill, m the mass of the ball, V the velocity at the base of the hill, g the gravity and h the altitude.

First, we will find the moment of inertia as:

I = $\frac{2}{3}mR^2$