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Maverick and goose are flying a training mission in their F-14. They are flying at an altitude of 1500 m and are traveling at 68

lions [1.4K]

Answer:

The bomb will remain in air for 17.5 s before hitting the ground.

Explanation:

Given:

Initial vertical height is, $y_0=1500\ m$

Initial horizontal velocity is, $u_x=688\ m/s$

Initial vertical velocity is, $u_y=0(\textrm{Horizontal velocity only initially)}$

Let the time taken by the bomb to reach the ground be 't'.

So, consider the equation of motion of the bomb in the vertical direction.

The displacement of the bomb vertically is $S=y-y_0=0-1500=-1500\ m$

Acceleration in the vertical direction is due to gravity, $g=-9.8\ m/s^2$

Therefore, the displacement of the bomb is given as:

$S=u_yt+\frac{1}{2}gt^2\\-1500=0-\frac{1}{2}(9.8)(t^2)\\1500=4.9t^2\\t^2=\frac{1500}{4.9}\\t=\sqrt{\frac{1500}{4.9}}=17.5\ s$

So, the bomb will remain in air for 17.5 s before hitting the ground.

5 0

3 years ago

Ton is used for measure very big masses. right or wrong science

nlexa [21]

Answer:

Explanation:

The correct answer is right

4 0

3 years ago

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An object with a mass of m = 3.85 kg is suspended at rest between the ceiling and the floor by two thin vertical ropes.

Aleksandr-060686 [28]

The tension in the upper rope is determined as 50.53 N.

<h3>Tension in the upper rope</h3>

The tension in the upper rope is calculated as follows;

T(u) = T(d)+ mg

where;

T(u) is tension in upper rope
T(d) is tension in lower rope

T(u) = 12.8 N + 3.85(9.8)

T(u) = 50.53 N

Thus, the tension in the upper rope is determined as 50.53 N.

Learn more about tension here: brainly.com/question/918617

#SPJ1

6 0

2 years ago

a bullet moving with a velocity of 100m/s pierce a block of wood and moves out with a velocityof 10 m/s.if the thickness of the

erma4kov [3.2K]

The emerging velocity of the bullet is 71 m/s.

The bullet of mass m moving with a velocity u has kinetic energy. When it pierces the block of wood, the block exerts a force of friction on the bullet. As the bullet passes through the block, work is done against the resistive forces exerted on the bullet by the block. This results in the reduction of the bullet's kinetic energy. The bullet has a speed v when it emerges from the block.

If the block exerts a resistive force F on the bullet and the thickness of the block is x then, the work done by the resistive force is given by,

$W=Fx$

This is equal to the change in the bullet's kinetic energy.

$W=Fx=\frac{1}{2} m(u^2-v^2)......(1)$

If the thickness of the block is reduced by one-half, the bullet emerges out with a velocity v₁.

Assuming the same resistive forces to act on the bullet,

$F(\frac{x}{2} )=\frac{1}{2} m(u^2-v_1^2)......(2)$

Divide equation (2) by equation (1) and simplify for v₁.

$\frac{\frac{Fx}{2} }{Fx} =\frac{(u^2-v_1^2)}{(u^2-v^2)} \\\frac{100^2-v_1^2}{100^2-10^2} =\frac{1}{2} \\v_1^2=5050\\v_1=71.06 m/s$

Thus the speed of the bullet is 71 m/s

3 0

3 years ago

Which graph represents the solution set of the system of inequalities? {−2x+y≤4y>x+2

Jet001 [13]

Answer:

The fourth graph is the answer

Explanation:

We have inequalities

$-2x+y\leq 4$ $\rightarrow y\leq 2x+4$

$y>x+2$

For the first inequality all points at or below the graph of y are solutions, and for the second inequality all the points above the graph of y are the solutions. So, the solution to these inequalities are points that are above the graph of $y>x+2$ and below the graph of $y\leq 2x+4$ . The shaded region in the fourth graph satisfies these conditions.

Looking at other choices, we see that the first two graphs do not even represent the graphs of our inequalities, and the third graph does represent the inequalities but shades the wrong region.

P.S: the graph of the inequality $y>x+2$ is dashed because $y$ is "greater than" and not "equal to" $x+2$ , so this indicates that the values on the line $y=x+2$ are not included. And the graph of the inequality $y\leq 2x+4$ is a solid line because $y$ is "less than or equal to" $2x+4$ , so we are including the values on the line $y=2x+4$ , and that's why it's solid.

6 0

3 years ago

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