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Elena L [17]
3 years ago
14

Help pls ... will give brainlist

Physics
1 answer:
Ghella [55]3 years ago
6 0
I, i’m pretty sure sorry if it’s wrong
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ANSWER ASAPPPPPPPP BE 100% CORRECT
AfilCa [17]
Mass of a sample of gas doesn't change, no matter what happens to its pressure, volume, or temperature.
7 0
3 years ago
What type of waves are sound waves, and how do they<br> transfer energy?
klemol [59]

Answer:

Sound wave types - longitudinal waves

Longitudinal waves - Vibrating string the creates sound in the way it moves.

Explanation:

Longitudinal waves have particles of the medium that are displaced in a parallel direction to energy transport.

7 0
3 years ago
How many milligrams in 1 gram. ??? HELP !!!
blagie [28]
1,000 milligrams = 1 gram
2,000 milligrams = 2 grams
3,000 milligrams = 3 grams
4,000 milligrams = 4 grams
3 0
3 years ago
Read 2 more answers
A 2.2 kgkg block slides along a frictionless surface at 1.2 m/sm/s . A second block, sliding at a faster 4.0 m/sm/s , collides w
aleksklad [387]

Answer:

0.6kg

Explanation:

the unknown here is the mass of the second block

applying the law of the conservation of momentum

m₁v₁ + m₂v₂ = (m₁ + m₂) v₃

where m₁=mass of first block=2.2kg

m₂=mass of colliding block= ?

v₁= velocity of first block=1.2m/s

v₂=velocity of colliding block=4.0m/s

v₃= final velocity of combined block=1.8m/s

applying the formula above

(2.2 × 1.2) + (m₂ × 4) = (2.2 + m₂) × 1.8

2.64 + 4m₂ = 3.96 + 1.8m₂

collecting like terms

4m₂ - 1.8m₂ = 3.96 - 2.64

2.2m₂=1.32

divide both sides by 2.2

m₂= 0.6kg

4 0
3 years ago
An object at 27°C has its temperature increased to 37°C.
Firlakuza [10]

Answer:

b. 14

Explanation:

T_{i} = Initial temperature = 27 °C = 27 + 273 = 300 K

T_{f} = Final temperature = 37 °C = 37 + 273 = 310 K

P_{i} = Initial Power radiated by the object

P_{f} = Final Power radiated by the object

We know that the power radiated is directly proportional to fourth power of the temperature. hence

\frac{P_{f}}{P_{i}} = \frac{T_{f}^{4} }{T_{i}^{4} }\\\frac{P_{f}}{P_{i}} = \frac{(310)^{4} }{(300)^{4} }\\\frac{P_{f}}{P_{i}} = 1.14\\P_{f} = (1.14) P_{i}

Percentage increase in power is given as

\frac{(P_{f} - P_{i})\times100}{P_{i}} \\\frac{((1.14) P_{i} - P_{i})\times100}{P_{i}} \\14

3 0
3 years ago
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