Answer:
0.01790670606142 we assume you converting between moles fe and gram. you can reveiw more details on each measurement unit: molecular weight of fe or grams the sI base unit for amount of substance is the mole.1 mole is equal to 1 moles fe,or 55.845 grams
He variable that a scientist changes when conducting an experiment is called the manipulated variable
Question:
a. a direct linear relationship
b. an inverse linear relationship
c. a direct nonlinear relationship
d. an inverse nonlinear relationship
Answer:
The correct option is;
d. An inverse nonlinear relationship
Explanation:
From the universal gas equation, we have;
P·V = n·R·T
Where we have the temperature, T and the number of moles, n constant, therefore, we have
P×V = Constant, because, R, the universal gas constant is also constant, hence;
P×V = C

Since P varies with V then the graphical relationship will be an inverse nonlinear as we have
V P C
1 5 5
2 2.5 5
3 1.67 5
4 1.25 5
5 1 5
6 0.83 5
7 0.7 5
8 0.63 5
9 0.56 5
10 0.5 5
Where:
V = Volume
P = Pressure
C = Constant = 5
P = C/V
The graph is attached.
Answer:
snow and very low temperatures are predicted for tomorrow.
Explanation:
snow and very low temperatures are associated with average weather condition of a place thus making it a statement about climate.
Answer:
0.6258 g
Explanation:
To determine the number grams of aluminum in the above reaction;
- determine the number of moles of HCl
- determine the mole ratio,
- use the mole ratio to calculate the number of moles of aluminum.
- use RFM of Aluminum to determine the grams required.
<u>Moles </u><u>of </u><u>HCl</u>
35 mL of 2.0 M HCl
2 moles of HCl is contained in 1000 mL
x moles of HCl is contained in 35 mL

We have 0.07 moles of HCl.
<u>Mole </u><u>ratio</u>
6HCl(aq) + 2Al(s) --> 2AlCl3(aq) + 3H2(g)
Hence mole ratio = 6 : 2 (HCl : Al
- but moles of HCl is 0.07, therefore the moles of Al;

Therefore we have 0.0233333 moles of aluminum.
<u>Grams of </u><u>Aluminum</u>
We use the formula;

The RFM (Relative formula mass) of aluminum is 26.982g/mol.
Substitute values into the formula;

The number of grams of aluminum required to react with HCl is 0.6258 g.