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3 years ago

Which of the following describes the relationship between the area of piston and the force exerted?

Physics

2 answers:

bearhunter [10]3 years ago

8 0

Answer:

Pascal`s Principle

Explanation:

kondor19780726 [428]3 years ago

3 0

Answer: Pascal’s principle (apex)

Hope this helps you out!

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A raft is made using a number of logs (TBD) with 25-cm diameter and 2-m-length. It is desired that a maximum 90 percent volume o

Vilka [71]

Answer:

6logs

Explanation:f

First finding the volume of the logs

V= π/4d²l

= 0.098m³

So number of logs will be

Weight of 2 boys + weight of log = buoyancy force.

2( 400)+ N ( Mlog x g) = density of water x volume displaced x g

2(400) = N x 0.098x 1000x 9.8 x 0.9- 0.75* 1000

N= 5.5 which is approx 6logs

3 0

3 years ago

The kettle is filled with 5.0 kg of water at 20 °C. The specific heat capacity of water = 4 200 J/Kg °C. Calculate the energy ne

Allisa [31]

Answer:

17 * 10^5 J

Explanation:

From;

H= mcΘ

where;

m = mass of water = 5.0 Kg

c = heat capacity of water = 4 200 J/Kg °C

Θ = temperature rise = 100 °C - 20 °C = 80°C

Substituting values;

H = 5 * 4 200 * 80

H = 17 * 10^5 J

4 0

3 years ago

a length of wire is cut into five equal pieces. the five pieces are then connected in parallel, with the resulting resistance be

Natali [406]

The equivalent resistance of n resistors connected in parallel is given by
$\frac{1}{R_{eq}} = \frac{1}{R_1}+ \frac{1}{R_2}+...+ \frac{1}{R_n}$ (1)

In our problem, the resulting resistance of the 5 pieces connected in parallel is $R_{Eq}=2.00 \Omega$ , and since the 5 pieces are identical, their resistance R is identical, so we can rewrite (1) as
$\frac{1}{R_{Eq} }= \frac{1}{2 \Omega}= \frac{1}{R}+ \frac{1}{R} + \frac{1}{R} + \frac{1}{R} + \frac{1}{R} = \frac{5}{R}$
From which we find $R= 5 \cdot 2 \Omega = 10 \Omega$ .

So, each piece of wire has a resistance of $10 \Omega$ . Before the wire was cut, the five pieces were connected as they were in series. The equivalent resistance of a series of n resistors is given by
$R_{Eq}=R_1 + R_2 + ...+R_n$
So if we apply it at our case, we have
$R_{eq}=R+R+R+R+R=5 R= 5\cdot 10 \Omega= 50 \Omega$

therefore, the resistance of the original wire was $50 \Omega$ .

5 0

3 years ago

One of Lex Luthor's henchman attacks Superman, shooting a rapid-fire stream of 3.3 g bullets at him at a rate of 112/min. The sp

igor_vitrenko [27]

Answer:

3.2451N

Explanation:

Mass of the bullet (m) $= 3.3g = 3.3*10^{-3}Kg$

Speed of the bullet (V) $= 527m/s$

Rate of bullet (r) $= 112/min = 1.866\sec$

We can calculate with this information the average acceleration of bullets

$a=V*r = 527\frac{m}{s}\frac{1.866}{s} = 983.38m/s^2$

The force is given by,

$F=ma\\F=(3.3*10^{-3})*983.38m/s^2 = 3.2451N$

That is just because he is Superman.

4 0

3 years ago

Consider a system consisting of the Earth, a vertical spring attached to the Earth, and a mass attached to the other end of the

Liula [17]

Answer:

The external force leads to an increase on gravitational and spring potential energies.

Explanation:

The system consists of a mass, resort and Earth. According to the Principle of Energy Conservation there is a potential energy as a consequence of the interaction between Earth and the mass and spring potential energy because of the spring deformation and, besides, the existence of work due to an external force:

$U_{g,A} + U_{k,A} + W_{ext} = U_{g,B} + U_{k,B}$

$W_{ext} = (U_{g,B}-U_{g,A}) + (U_{k,B}-U_{k,A})$

$F\cdot \Delta r = \frac{G\cdot m\cdot M}{r_{o}-\Delta r} - \frac{G\cdot m \cdot M}{r_{o}} +\frac{1}{2}\cdot k \cdot (x_{o}+\Delta r)^{2} - \frac{1}{2} \cdot k \cdot (x_{o})^{2}$

$F\cdot \Delta r = G\cdot m \cdot M \cdot \left(\frac{1}{r_{o}-\Delta r}-\frac{1}{r_{o}} \right)+\frac{1}{2}\cdot k \cdot [(x_{o}+\Delta r)^{2} -x_{o}^{2}]$

The external force leads to an increase on gravitational and spring potential energies.

7 0

3 years ago

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