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Paul [167]
4 years ago
13

How do we measure the acidity of rain?

Chemistry
2 answers:
Leona [35]4 years ago
6 0
Just use litmus paper or a pH indicator
bija089 [108]4 years ago
3 0
Through pH scale. it measures the acidity of a substance, pH is measured with a litmus paper, if the paper turns red then it is acidic.
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What's the chemical formula for salt, like is it NaCl?? <br>the salt we eat???????​
MA_775_DIABLO [31]

yeah it's NaCl, I just looked it up

3 0
3 years ago
Read 2 more answers
If a solution containing 23.81 g of lead(II) acetate is allowed to react completely with a solution containing 7.410 g of sodium
jeka57 [31]

Answer:

The correct answer is 15.80 grams.

Explanation:

The reaction taking place in the given question,  

Pb(CH₃COO)₂ + Na₂SO₄ ⇒ PbSO₄ + 2NaCH₃COO

The number of moles can be calculated by using the formula,  

n = weight / molecular mass

Based on the given question, the weight of lead (II) acetate is 23.81 grams and the weight of sodium sulfate is 7.410 grams.  

The number of moles of Pb(CH₃COO)₂ is,  

n = 23.81 g / 325.29 g/mol = 0.0732 moles

The number of moles of Na₂SO₄ is,  

n = 7.410 g / 142.04 g/mol = 0.0521 moles

As one mole of lead (II) acetate needs one mole of sodium sulfate. Therefore, 0.0732 moles of lead (II) acetate needs 0.0732 moles of sodium sulfate.  

However, as sodium sulfate is less, that is, 0.0521, therefore, Na₂SO₄ is a limiting reactant.  

One mole of sodium sulfate produces one mole of PbSO₄. So, 0.0521 moles of Na₂SO₄ produces 0.0521 moles of PbSO₄.  

Now the mass of PbSO₄ is,  

mass = moles × molecular mass

mass = 0.0521 × 303.26 g/mol

mass = 15.80 grams.  

6 0
3 years ago
One mole of carbon (12.0 g) in the form of crystalline graphite is burned at 25◦C and 1.000 atm pressure to form CO2(g). All of
iogann1982 [59]

Answer:

T₂ = 43.46 °C  

Explanation:

Given that:

The heat of the formation of carbon dioxide = - 393.5 kJ/mol (Negative sign suggests heat loss)

It means that energy released when 1 mole of carbon undergoes combustion = 393.5 kJ = 393500 J

Heat gain by water = Heat lost by the reaction

Thus,    

m_{water}\times C_{water}\times \Delta T=Q

For water:  

Mass of water  = 5100 g

Specific heat of water = 4.18 J/g°C  

T₁ = 25 °C  

T₂ = ?

Q = 393500 J

So,

5100\times 4.18\times (T_2-25)=393500  

T₂ = 43.46 °C  

6 0
3 years ago
What is the mass, in grams, of 2.50 * 10-3 mol of aluminum sulfate?
Nonamiya [84]

Answer:

The mass is 0.855 grams (option A)

Explanation:

Step 1: Data given

aluminium sulfate = Al2(SO4)3

Numer of moles Al2(SO4)3 = 2.50 * 10^-3 moles

atomic mass Al = 26.99 g/mol

atomic mass S = 32.065 g/mol

Atomic mass O = 16 g/mol

Step 2: Calculate molar mass Al2(SO4)3

Molar mass = 2* 26.99 + 3*32.065 + 12*16

Molar mas = 342.175 g/mol

Step 3: Calculate mass Al2(SO4)3

Mass Al2(SO4)3 = moles Al2(SO4)3 * molar mass Al2(SO4)3

Mass Al2(SO4)3 = 2.5 *10^-3 moles * 342.175 g/mol

Mass Al2(SO4)3 = 0.855 grams

The mass is 0.855 grams (option A)

5 0
3 years ago
The number 89.667 rounded off to three significant figures is
Mariana [72]

Answer:

89.7

Explanation:

First we have to look at the right of the digit which is going to be round. If it is 5 or greater than 5 than the number left to it should be increased by one.

For example

In given number 89.667 after three digits 8, 9, 6 the next digit is 6.

So in order to round the number to three digits 6 will rounded to 7 and value becomes 89.7

If the digit next to rounded digit is less than 5 than number will rounded as,

For example:

56.42

Rounded to three digit it will be 56.4.

3 0
3 years ago
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