A beaker contains 249 mL of a 6.54 M HCl(aq) solution. Determine the new concentration of the solution after it is diluted by ad
1 answer:
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Answer:
Explanation:
2 HgCl₂ + C₂O₄²⁻ = 2 Cl⁻ + Hg₂Cl₂ + 2CO₂
1 )
Rate of reaction
[HgCl₂] [C₂O₄²⁻ ] Rate
1 . .124 .115 1.61 x 10⁻⁵
2 . .248 .115 3.23 x 10⁻⁵
3 . .124 .229 6.4 x 10⁻⁵
4 . .248 .229 1.28 x 10⁻⁴
comparing 1 and 3 , when concentration of HgCl₂ remains constant and concentration of C₂O₄²⁻ becomes twice , rate becomes 4 times so rate is proportional to square of concentration of C₂O₄²⁻ .
Hence n = 2
comparing 1 and 2 , when concentration of HgCl₂ becomes twice and concentration of C₂O₄²⁻ remains constant , rate becomes 2 times so rate is proportional to simply concentration of C₂O₄²⁻ .
Hence m = 1
Putting the data of 1 in the rate equation found
1.61 x 10⁻⁵ = k x .124 x .115²
k = 11.3 x 10⁻⁴ M⁻² s⁻¹