Question

A beaker contains 249 mL of a 6.54 M HCl(aq) solution. Determine the new concentration of the solution after it is diluted by adding 167 mL of water to the beaker. Express the concentration in molarity to three significant figures.

Answer 1

Answer:

The new molarity is 0.614 M

Explanation:

Formula for dilutions is:

M concentrated . Volume of conc = Volume of dil . M diluted

6.54 M . 249 mL = 416 mL . M diluted

Notice that volume of diluted is = Initial volume + What we added of water

(249mL + 167 mL)

(6.54 M . 249 mL) / 416mL = M diluted → 0.614 M